The common difference of the data set of A is 1. While the common difference in the data set of B is 0.80
B.) 3.8 + 0.80 = 4.60
4.6 + 0.80 = 5.40
5.4 + 0.80 = 6.20
6.2 + 0.80 = 7.00
Answer:
CDE = 42
EDC = 97
BCA = 41
ABC = 85
BAC = 54
Step-by-step explanation:
See the picture for the explanation
Answer:
the answer is 24...........................
A senior ticket costs $10, while a student ticket costs $8. You can solve this system of equations by the elimination method.
We can use x as the variable for the senior tickets, and y as the variable for the student tickets and represent it with these equations:
10x+12y=212 and 12x+14y=232
Next, multiply each entire equation by a variable so they can eliminate each other. I used 12 and -10 here so it would be 120x-120x to eliminate that variable.
12(10x+14y=212) and -10(12x+14y=232)
Our new equations are:
(120x +168y= 2544) and (-120x-140y=-2320)
You can then subtract one of the equations from the other leaving you with 28y=224 and solve it for y to get 8.
So the price of a student ticket is 8.
Pick any of the original equations and by replacing y with 8, you can solve to find x. (X is the variable we assigned for senior tickets)
10x+14(8)=212
10x+112=212
10x=212-112
10x= 100
1x=10