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3 years ago

Write your schedule for today list each activity with with it starting to write

1 answer:

6 0

My schedule for today is as follows;)
6am - 7am - refreshing (like brushing the teeth,having coffee or milk , bathing etc..)
7am - 7:30am - having breakfast
7:30am - 1 pm - In school (studying , playing etc..
1pm - 1:30 pm - having lunch
1:30pm - 4pm - studying any subject or what happened in school
4pm - 6pm - playing outdoor games
6pm - 7pm - watching TV , refreshing
7pm - 8:30 pm - studying , doing homework
8:30pm - 9pm - having dinner
9pm - 10pm - watching TV
10pm - 6am - sleeping

You might be interested in

Your Numbers are; 25, 75, 50, 1, 9, 3 and your Target is 386 How do i get to 386 using only these numbers once and I can use Sub

GuDViN [60]

Answer:

You must order the operations in the way that it unfolds in the explanation;:

Step-by-step explanation:

(25 x 9) +75 + 50+ 9 x ( 3 + 1)

When performing the operations we have the following results:

(25 x 9) =225 +75= 300+50 = 350+9 = 359 x (3+1 )

Now we must solve the following: 359 x (4) = 386

8 0

3 years ago

Suppose Upper F Superscript prime Baseline left-parenthesis x right-parenthesis equals 3 x Superscript 2 Baseline plus 7 and Upp

Sedaia [141]

It looks like you're given

F'(x) = 3x² + 7

and

F (0) = 5

and you're asked to find F(b) for the values of b in the list {0, 0.1, 0.2, 0.5, 2.0}.

The first is done for you, F (0) = 5.

For the remaining b, you can solve for F(x) exactly by using the fundamental theorem of calculus:

$F(x)=F(0)+\displaystyle\int_0^x F'(t)\,\mathrm dt$

$F(x)=5+\displaystyle\int_0^x(3t^2+7)\,\mathrm dt$

$F(x)=5+(t^3+7t)\bigg|_0^x$

$F(x)=5+x^3+7x$

Then F (0.1) = 5.701, F (0.2) = 6.408, F (0.5) = 8.625, and F (2.0) = 27.

On the other hand, if you're expected to approximate F at the given b, you can use the linear approximation to F(x) around x = 0, which is

F(x) ≈ L(x) = F (0) + F' (0) (x - 0) = 5 + 7x

Then F (0) = 5, F (0.1) ≈ 5.7, F (0.2) ≈ 6.4, F (0.5) ≈ 8.5, and F (2.0) ≈ 19. Notice how the error gets larger the further away b gets from 0.

A better numerical method would be Euler's method. Given F'(x), we iteratively use the linear approximation at successive points to get closer approximations to the actual values of F(x).

Let y(x) = F(x). Starting with x₀ = 0 and y₀ = F(x₀) = 5, we have

x₁ = x₀ + 0.1 = 0.1

y₁ = y₀ + F'(x₀) (x₁ - x₀) = 5 + 7 (0.1 - 0) → F (0.1) ≈ 5.7

x₂ = x₁ + 0.1 = 0.2

y₂ = y₁ + F'(x₁) (x₂ - x₁) = 5.7 + 7.03 (0.2 - 0.1) → F (0.2) ≈ 6.403

x₃ = x₂ + 0.3 = 0.5

y₃ = y₂ + F'(x₂) (x₃ - x₂) = 6.403 + 7.12 (0.5 - 0.2) → F (0.5) ≈ 8.539

x₄ = x₃ + 1.5 = 2.0

y₄ = y₃ + F'(x₃) (x₄ - x₃) = 8.539 + 7.75 (2.0 - 0.5) → F (2.0) ≈ 20.164

4 0

3 years ago

Factor 26r3s + 52r5 – 39r2s4.

algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> 13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)

To factor it all together;

13r²(2rs + 4r³ - 3s⁴)

Hope this helps!

7 0

3 years ago

Which ordered pair is a solution to the system of linear equations One-half x minus three-fourths y = StartFraction 11 Over 60 E

s344n2d4d5 [400]

Answer:

$\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

Step-by-step explanation:

Given the system of two equations:

$\left\{\begin{array}{l}\dfrac{1}{2}x-\dfrac{3}{4}y=\dfrac{11}{60}\\ \\\dfrac{2}{5}x+\dfrac{1}{6}y=\dfrac{3}{10}\end{array}\right.$

Multiply the first equation and the second equation by 60 to get rid of fractions:

$\left\{\begin{array}{l}30x-45y=11\\ \\24x+10y=18\end{array}\right.$

Now multiply the first equation by 4 and the second equation by 5:

$\left\{\begin{array}{l}120x-180y=44\\ \\120x+50y=90\end{array}\right.$

Subtract them:

$(120x-180y)-(120x+50y)=44-90\\ \\120x-180y-120x-50y=-46\\ \\-230y=-46\\ \\y=\dfrac{46}{230}=\dfrac{1}{5}$

Substitute it into the first equation:

$30x-45\cdot \dfrac{1}{5}=11\\ \\30x-9=11\\ \\30x=11+9\\ \\30x=20\\ \\x=\dfrac{2}{3}$

The solution is $\left(\dfrac{2}{3},\dfrac{1}{5}\right)$

4 0

3 years ago

Read 2 more answers

how many gallons will it take to mow a lawn if you maintain the rate of 1/2 gallon of gasoline per 1/4 mowed

Musya8 [376]

Recall that one whole is 1, or in this case since the denominator is 4, then 4/4 is 1 whole, so the whole lawn is 4/4.

$\bf \begin{array}{ccll}
gallons&mowed\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
\frac{1}{2}&\frac{1}{4}\\\\
g&\frac{4}{4}
\end{array}\implies \cfrac{\frac{1}{2}}{g}=\cfrac{\frac{1}{4}}{\frac{4}{4}}\implies \cfrac{\frac{1}{2}}{\frac{g}{1}}=\cfrac{\frac{1}{4}}{\frac{4}{4}}\implies \cfrac{1}{2}\cdot \cfrac{1}{g}=\cfrac{1}{4}\cdot \cfrac{4}{4}
\\\\\\
\cfrac{1}{2g}=\cfrac{1}{4}\implies 4=2g\implies \cfrac{4}{2}=g\implies 2=g$

3 0

3 years ago