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Yuri [45]
3 years ago
7

Rework problem 28 from section 3.1 of your text, involving the inspection of refrigerators on an assembly line. You should still

assume that no refrigerator has both too much and too little enamel; however, use the table below instead of that given in your book to answer the following questions.
Mathematics
1 answer:
sergeinik [125]3 years ago
3 0
Event: Probability: A. Too much enamel 0.18 B. Too little enamel 0.24 C. Uneven application 0.33 D. No defects noted 0.47 


let P(AC) = x, P(BC) = y, then P(A) + P(B) + P(C) - (x+y) = 1-0.47 = 0.53 x+y = 0.22 
3. The probability of paint defects that results to <span>an improper amount of paint and uneven application? </span>
 P(A U B U C) = 0.53 

4. <span>the probability of a paint defect that results to</span>
<span>the proper amount of paint, but uneven application?</span>
P(C) - P(AC) - P(BC) = 0.47 - 0.22 = 0.25 


A and B are disjoint so P(ABC) = 0, but you can have P(AC) and P(BC). you can't compute these separately here, but you can compute P(AC) + P(BC). By the way, P(AC) eg is just an abbreviated version of P(A∩C).
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Set the function up in integral form and evaluate to find the integral.
F(x)=F(x)=12x2−ln(|x|)−1x2+C
3 0
3 years ago
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3 years ago
1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into
iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

D=1500-1466=34

6 0
3 years ago
6. Evaluate /(x) = -4x - 5 for x = -1.
Stels [109]

Answer:

-1

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3 0
3 years ago
A is the smallest two digit whole number; "b" is the sum of prime numbers up to 10. what is a b?
Natasha2012 [34]
Whole numbers are like 0,1,2,3,4,5...
the smallest one is 10

prime numbers
I do not accept 1 as a prime number, if you agree, go to AAAAAAAAA
if you do think it's a prime number, go to BBBBBBB

AAAAAAA
2,3,5,7
2+3+5+7=17
a+b=10+17=27

BBBBBBBBBBB
1,2,3,5,7
1+2+3+5+7=18
a+b=10+18=28

if  you do not think a is a prime number, then the answer is 27
if you do think 1 is prime number then the answer is 28
5 0
2 years ago
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