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makvit [3.9K]
2 years ago
14

Kadeesha has a toy car collection of 320 toy cars. She keeps 85% of the toy cars on

Mathematics
1 answer:
aniked [119]2 years ago
5 0

Answer:

272

Step-by-step explanation:

320 * 85%

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and
nasty-shy [4]

Answer:

correct option is C)  2.8

Step-by-step explanation:

given data

string vibrates form =  8 loops

in water loop formed =  10 loops

solution

we consider  mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = \rho

case (1)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

so here

l = \frac{8 \lambda _1}{2}      ..............1

l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}

and we know velocity is express as

velocity = frequency × wavelength   .....................2

\sqrt{\frac{Tension}{mass\ per\ unit \length }}   =   f × \lambda_1

here tension = mg

so

\sqrt{\frac{mg}{\mu}}   =   f × \lambda_1     ..........................3

and

case (2)  

when 8 loop form with 2 adjacent node is \frac{\lambda }{2}

l = \frac{10 \lambda _1}{2}      ..............4

l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}

when block is immersed

equilibrium  eq will be

Tenion + force of buoyancy = mg

T + v × \rho × g = mg

and

T = v × \rho - v × \rho × g    

from equation 2

f × \lambda_2 = f  × \frac{1}{5}  

\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}     .......................5

now we divide eq 5 by the eq 3

\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}

solve irt we get

1 - \frac{\rho _{stone}}{\rho _{water}}  = \frac{16}{25}

so

relative density \frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}

relative density = 2.78 ≈ 2.8

so correct option is C)  2.8

3 0
3 years ago
Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma
Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = x

Using unitary method to find weight of x horses.

If 1 horse weights = 1,200 lb

Then x horses will weight in lbs = 1,200\times x = 1,200x

Total weight of horses and trailer in lbs = 1200x+2700

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

1200x+2700\leq5000

Subtracting both sides by 2700.

1200x+2700-2700\leq5000-2700

1200x\leq2300

Dividing both sides by 1200.

\frac{1200x}{1200}\leq\frac{2300}{1200}

x\leq1.91

From the inequality solution for x, we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0
3 years ago
Need done asap !!
damaskus [11]
PointA is (-8,4)
PointB is (8,-4)
Rate of change is -1/2

4 0
1 year ago
How do i solve 16x+9=9y-2x
Misha Larkins [42]

Answer:

18x+9=9y

Step-by-step explanation:

16x+9=9y-2x

+2x         +2x

18x+9=9y

4 0
3 years ago
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Open US_Crime-HW7 data. Test if West Virginia’s vehicle thefts are lower than Nebraska’s vehicle thefts on average. Answer quest
marysya [2.9K]

Answer:

c. One sided t-test

Step-by-step explanation:

One sided t test because we want to compare two means and alternative hypothesis is directional.

8 0
3 years ago
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