Kadeesha has a toy car collection of 320 toy cars. She keeps 85% of the toy cars on

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

so

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

so

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Jake is using a horse trailer to take his horses to his new ranch. 1 Horse= 1,200 lb Trailer= 2,700 lb Jake's truck can tow a ma

Kitty [74]

Answer:

Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

Step-by-step explanation:

Given:

Weight of 1 horse = 1,200 lb

Weight of trailer = 2,700 lb

Jacks'truck can tow a maximum of 5000 pounds.

To find the maximum number of horses Jack can take in his trailer without going over the maximum weight his truck can tow.

Solution:

Let the maximum number of horses that Jack can take be = $x$

Using unitary method to find weight of $x$ horses.

If 1 horse weights = 1,200 lb

Then $x$ horses will weight in lbs = $1,200\times x = 1,200x$

Total weight of horses and trailer in lbs = $1200x+2700$

Since the maximum weight the truck can tow = 5,000 lb, so the inequality can be given as:

$1200x+2700\leq5000$

Subtracting both sides by 2700.

$1200x+2700-2700\leq5000-2700$

$1200x\leq2300$

Dividing both sides by 1200.

$\frac{1200x}{1200}\leq\frac{2300}{1200}$

$x\leq1.91$

From the inequality solution for $x$ , we can conclude that Jack can take only 1 horse on his trailer to be towed by the truck without going over the maximum weight the truck.

3 0

3 years ago

Need done asap !!

damaskus [11]

PointA is (-8,4)
PointB is (8,-4)
Rate of change is -1/2

4 0

1 year ago

How do i solve 16x+9=9y-2x

Misha Larkins [42]

Answer:

18x+9=9y

Step-by-step explanation:

16x+9=9y-2x

+2x +2x

18x+9=9y

4 0

3 years ago

Read 2 more answers

Open US_Crime-HW7 data. Test if West Virginia’s vehicle thefts are lower than Nebraska’s vehicle thefts on average. Answer quest

marysya [2.9K]

Answer:

c. One sided t-test

Step-by-step explanation:

One sided t test because we want to compare two means and alternative hypothesis is directional.

8 0

3 years ago