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makvit [3.9K]
1 year ago
14

Kadeesha has a toy car collection of 320 toy cars. She keeps 85% of the toy cars on

Mathematics
1 answer:
aniked [119]1 year ago
5 0

Answer:

272

Step-by-step explanation:

320 * 85%

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This question on math and needs to be written a proportion
guapka [62]

Answer:

g = 3

Step-by-step explanation:

miles / gallon = miles / gallon

104 / 4 = 78 / g

cross-multiply to solve for 'g':

78(4) = 104g

312 = 104g

312/104 = g

3 = g

4 0
2 years ago
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Integers with different values in each digit can be expanded in a similar way. For these integers, you must use addition between
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3 years ago
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Say you want to buy x shirts which cost 2$ each and add tax which is $0.75. You have 13$ to make your purchase.
kobusy [5.1K]
EDIT: 
2x + 0.75 = 13
Add like terms
2x= 13-0.75
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x= 12.25/2
x=6.125
You can buy 6 whole shirts with $0.25 left over

Hope this helps! A thanks/brainliest answer would be appreciated :)
3 0
3 years ago
The function y = f(x) is graphed below. What is the average rate of change of the
Serjik [45]

The average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

<h3>What is the average rate of change?</h3>

The average Rate of Change of the function f(x) can be calculated as;

f(x) = \dfrac{f(b) - f(a)}{b-a}

Interval -3 ≤ x ≤-1

a = -3, b = -1

f(a) = f(-3) = -20

f(b) = f(-1) = 0

Step 2: Find Average

f(x) = \dfrac{f(b) - f(a)}{b-a}\\\\\\f(x) = \dfrac{f(-1) - f(-3)}{-1-(-3)}\\\\\\f(x) = \dfrac{0 - (-20)}{2}\\\\f(x) = 10

Therefore, the average rate of change of the function in the given interval -3 ≤ x ≤-1 is 10.

Learn more about average rate;

brainly.com/question/20784578

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3 0
1 year ago
A fluid moves through a tube of length 1 meter and radius r=0.006±0.00025 meters under a pressure p=4⋅105±2000 pascals, at a rat
iris [78.8K]

Answer:

Maximum error for viscosity is 17.14%

Step-by-step explanation:

We know that everything is changing with respect to the time, "r" is changing with respect to the time, and also "p" just "v" will not change with the time according to the information given, so we can find the implicit derivative with respect to the time, and since

n = (\frac{\pi}{8}) (\frac{pr^4}{v})\\

The implicit derivative with respect to the time would be

\frac{dn}{dt}  = \frac{\pi}{8} ( \frac{r^4}{v} \frac{dp}{dt}  + \frac{4pr^3}{v}\frac{dr}{dt} )

If we multiply everything by    dt   we get  

dn  = \frac{\pi}{8} ( \frac{r^4}{v} dp  + \frac{4pr^3}{v}  dr})

Remember that  the error is given by   \frac{dn}{n}   therefore doing some algebra we get that

\frac{dn}{n}  =    4 \frac{dr}{r}  +  \frac{dp}{p}

Since,    r = 0.006   ,   dr = 0.00025 ,  p = 4*105   ,   dp = 2000  we get that

\frac{dn}{n} = 0.1714

Which means that  the maximum error for viscosity is 17.14%.  

5 0
3 years ago
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