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frez [133]
3 years ago
11

ASAP or when any one can

Mathematics
1 answer:
blondinia [14]3 years ago
3 0

between 15.8 and24.2 yrs

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FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Select all the expressions that are equivalent to −5/6 / -1/3
Sindrei [870]

Step-by-step explanation:

We need to find an expression for \dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}.

We can solve it as follows.

We know that,

\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}

So,

\dfrac{\dfrac{-5}{6}}{\dfrac{-1}{3}}=\dfrac{-5}{6}\times -3\\\\=\dfrac{5}{2}

or

=2\dfrac{1}{2}

Hence, this is the required solution.

3 0
2 years ago
Please i suck at math lol 2.0
Salsk061 [2.6K]

Answer:

i- ;-;

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Write the equation of the line containing each pair of points
Alja [10]
Can you please take a picture of each pair of points
4 0
3 years ago
For homework a student had to complete 15 problems total. If she finished 6 problems in class, what is the ratio of problems she
nexus9112 [7]

Well if the student already finished 6 problems out of 15, there are 15-6 = 9 homework questions she still has to finish.

Still needs to complete: 9.

Already finished: 6

9 : 6.

Simplified: 3 : 2

6 0
3 years ago
Read 2 more answers
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