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dimaraw [331]
2 years ago
11

There are 10 USB drives in a box and 3 are defective. Two drives are to be selected, one after the other. What is the probabilit

y of selecting a defective USB followed by another defective USB?
Mathematics
1 answer:
Lynna [10]2 years ago
5 0

|\Omega|=10\cdot9=90\\|A|=3\cdot2=6\\\\P(A)=\dfrac{6}{90}=\dfrac{1}{15}\approx6.7\%

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