Answer:
D
A=-5
Step-by-step explanation:
Answer:
22
Step-by-step explanation:
Pretend the 10 values in the first sentence are a,b,c,d,e,f,g,h,i,j
Pretend the addition 5 values is k,l,m,n,o
So the mean of all the 15 data is (a+b+c+d+e+f+g+h+i+j+k+l+m+n+o)/15=20
So the sum of all 15 data is a+b+c+d+e+f+g+h+i+j+k+l+m+n+o=300 since 15(20)=300
Now let's look at the first 10: We have their mean so we can write:
(a+b+c+d+e+f+g+h+i+j)/10=19
so a+b+c+d+e+f+g+h+i+j=190 since 10(19)=190
So that means using our first sum equation and our equation sum equation we have
190+k+l+m+n+o=300
k+l+m+n+o=300-190
k+l+m+n+o= 110
So the average of those 5 numbers mentioned in your problem is 110/5=22
Answer:
Ans: (-5, 5)
-5 < x < 5
Step-by-step explanation:
Standard form: f(x) = x^2 - 25 < 0.
First solve x^2 - 25 = 0 --> x = +- 5
Use the algebraic method to solve f(x) < 0. Between the 2 real roots (-5) and (5), f(x) < 0, as opposite in sign to a = 1.
Answer by open interval: (-5, 5)
Answer:
The maximum power generated by the circuit is 300 watts.
Step-by-step explanation:
A quadratic function is one that can be written as an equation of the form:
f (x) = ax² + bx + c
where a, b and c (called terms) are any real numbers and a is nonzero.
In this case, f(x) is P(c) [the power generated], x is the current c (in amperes), a = -12, b = 120 and c = 0.
The vertex is a point that is part of the parabola, which has the value as ordered minimum or maximum function. If the scalar a> 0, the parabola opens or faces up and the vertex is the minimum of the function. In contrast, if a <0, the parabola opens downward and the vertex is the maximum of the function.
The calculation of the vertex, which in this case will be the maximum of the function, is carried out as follows:
- The value of x, in this case the value of current c in amperes, can be calculated with the formula
. In this case:
So c= 5 amperes. The current is 5 amperes. - The value of y, in this case the value of the electric current in watts, is obtained by substituting the value of c previously obtained in the function. In this case: P(5)= -12*5²+120*5. So P(5)= 300 watts
<u><em>The maximum power generated by the circuit is 300 watts.</em></u>
It is 15100. First 0 is no important.