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2 years ago

Somebody please help me

Mathematics

2 answers:

ss7ja [257]2 years ago

7 0

Answer:

2, -1

Step-by-step explanation:

That seems like what the midpoint is to the picture

Elza [17]2 years ago

5 0

Answer:

2, -1

Step-by-step explanation:

Edge2022

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Maya spent her allowance on playing an arcade game a few times and riding the Ferris wheel more than once.

NISA [10]

Answer:

To write a two-variable equation, I would first need to know how much Maya’s allowance was. Then, I would need the cost of playing the arcade game and of riding the Ferris wheel. I could let the equation be cost of playing the arcade games plus cost of riding the Ferris wheel equals the total allowance. My variables would represent the number of times Maya played the arcade game and the number of times she rode the Ferris wheel. With this equation I could solve for how many times she rode the Ferris wheel given the number of times she played the arcade game.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help !!! What’s the answer to this??

Aleksandr [31]

Answer:

Average speed is distance/time. You could say, 12/6 = 2 miles per second and say that’s the answer, but we relate to mph so much better. Since there are 60 x 60 = 3600 sec in an hour, that same speed is:

2 x 3600 = 7,200 mph

No “car” can travel this fast. Some rocket cars have gone about 1/10th this speed.

7 0

2 years ago

The polar curve $r = 1 + \cos \theta$ is rotated once around the point with polar coordinates $(2,0).$ What is the area of the r

mash [69]

Answer:

$Area = -2.3147$

Step-by-step explanation:

Given

$r = 1 + \cos \theta$

Required

Determine the area with coordinates $(2,0)$

The area is represented as:

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

Where

$r = 1 + \cos \theta$

and

$(a,b) = (2,0)$

Substitute values for r, a and b in

$Area = \frac{1}{2}\int\limits^b_a {r^2} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)^2} \, d\theta$

Expand

$Area = \frac{1}{2}\int\limits^0_2 {(1 + cos\theta)(1 + cos\theta)} \, d\theta$

$Area = \frac{1}{2}\int\limits^0_2 {(1 + 2cos\theta+cos^2\theta} )\, d\theta$

By integratin the above, we get:

$Area = \frac{1}{2}*\frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{2}[0,2]$

$Area = \frac{(cos(\theta) + 4)sin(\theta) + 3\theta}{4}[0,2]$

Substitute 0 and 2 for $\theta$ one after the other

$Area = \frac{(cos(0) + 4)sin(0) + 3*0}{4} - \frac{(cos(2) + 4)sin(2) + 3*2}{4}$

$Area = \frac{(cos(0) + 4)sin(0)}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{(1 + 4)*0}{4} - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = - \frac{(cos(2) + 4)sin(2) + 6}{4}$

$Area = \frac{-sin(2)(cos(2) + 4) - 6}{4}$

Get sin(2) and cos(2) in radians

$Area = \frac{-0.9093 * (-0.4161 + 4) - 6}{4}$

$Area = \frac{-9.2588}{4}$

$Area = -2.3147$

3 0

3 years ago

In a baseball league consisting of 12 teams, each team plays each of the other teams twice. How many games will be played? There

saul85 [17]

Answer:

132 games played.

Step-by-step explanation:

Let x be the

We have been given that in a baseball league consisting of 12 teams, each team plays each of the other teams twice.

Since there are 12 teams, so each team will play with $(12-1)$ teams except itself.

The total number of games played would be 12 times $(12-1)$ :

$\text{The total number of games played}=12(12-1)$

$\text{The total number of games played}=12(11)$

$\text{The total number of games played}=132$

Therefore, there will be 132 games played.

4 0

3 years ago

A university financial aid office polled a random sample of 670 male undergraduate students and 617 female undergraduate student

ahrayia [7]

Answer:

The 90% confidence interval for the difference between the proportions of male and female students who were employed during the summer is (0.01, 0.1012).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean $\mu = p$ and standard deviation $s = \sqrt{\frac{p(1-p)}{n}}$

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Male undergraduates:

670, 388 were employed. So

$p_M = \frac{388}{670} = 0.5791$

$s_M = \sqrt{\frac{0.5791*0.4209}{670}} = 0.0191$

Female undergraduates:

Of 617, 323 were employed. So

$p_F = \frac{323}{617} = 0.5235$

$s_F = \sqrt{\frac{0.5235*0.4765}{617}} = 0.0201$

Distribution of the difference:

$p = p_M - p_F = 0.5791 - 0.5235 = 0.0556$

$s = sqrt{s_M^2+s_F^2} = \sqrt{0.0201^2 + 0.0191^2} = 0.0277$

Confidence interval:

The confidence interval is given by:

$p \pm zs$

In which

z is the z-score that has a p-value of $1 - \frac{\alpha}{2}$ .

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a p-value of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

The lower bound of the interval is:

$p - zs = 0.0556 - 1.645*0.0277 = 0.01$

The upper bound of the interval is:

$p + zs = 0.0556 + 1.645*0.0277 = 0.1012$

The 90% confidence interval for the difference between the proportions of male and female students who were employed during the summer is (0.01, 0.1012).

5 0

3 years ago