Please help - A trapezoid has a set of parallel bases with lengths 3 inches and 5 inches and a height of 8 inches. What is the a
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Answer:
? = 13.6
Step-by-step explanation:
the angle between a tangent and the diameter = 90°
Then the triangle is right with legs 2 × 6 = 12 and 6.4
using Pythagoras' identity in the right triangle.
the square on the hypotenuse is equal to the sum of the squares on the legs , that is
? ² = 12² + 6.4² = 144 + 40.96 = 184.96 ( take square root of both sides )
? = = 13.6
If you notice the picture below
the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it
so.. get the area of the trapezoid
then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh
then, subtract the triangle's area from the rectangle's area
and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area
namely the area of the trapezoid plus the rectangle's, minus the triangle's
the composite figure is just a trapezoid sitting on top of a rectangle
and then, the rectangle has a triangular hole in it
so.. get the area of the trapezoid
then get the area of the rectangle, which is just a 12x14
and then get the area of the triangle, which surely you know is 1/2 bh
then, subtract the triangle's area from the rectangle's area
and whatever is left, namely the difference, add that to the area of the trapezoid, and that's the composite's area
namely the area of the trapezoid plus the rectangle's, minus the triangle's