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horrorfan [7]
2 years ago
14

Surprisingly, many of us may be unknowing victims of botnets. Because of the rising sophistication of botnet schemes, your compu

ter can become a zombie along with thousands of other computers that flood a victim's network and bring down servers. While the attack is going on, the botnet infects the network with spam, viruses, and malware.
What are the four simple rules of stopping botnets on your personal PCs?

What are some of the symptoms that would make you suspicious that your computer has been attacked?

What part of a security incident should be logged?
Computers and Technology
1 answer:
Virty [35]2 years ago
7 0

Answer:

a. Simple rules

1. Upgrade your operating system

2. Upgrade your softwares regularly

3. Upgrade your browser when new additions are available

4. Change your password very often

b. Suspensious signs

1. The operating system and programs take a longer while to start up.

2. It shows lack of storage space despite having space

3. The PC crashes regularly

4. If the sent mails are received as spam

5. The hard disk is working excessively while no programs are currently running

C. All the part of a security incident should be logged.

Explanation:

a. Simple rules

1. Upgrade your operating system

2. Upgrade your softwares regularly

3. Upgrade your browser when new additions are available

4. Change your password very often

b. Suspensious signs

1. The operating system and programs take a longer while to start up.

2. It shows lack of storage space despite having space

3. The PC crashes regularly

4. If the sent mails are received as spam

5. The hard disk is working excessively while no programs are currently running

Explanation:

C. All the part of a security incident should be logged.

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The access code for a? car's security system consists of fivefive digits. the first digit cannot be zerozero and the last digit
jekas [21]
The code of five digits is of the form:

A B C D F

Where A (the first digit)  may be any of 9 digits (because 0 is excluded)

B, C, and D, may be each any of 10 digits (0 - 9)


F (the last digit) may be 0, 2, 4, 6 or 8, i.e. 5 different digits.


So the number of different available codes is:

9 * 10 * 10 * 10 * 5 = 45,000.


Answer: 45,000
4 0
2 years ago
What does brainliest do?
balandron [24]

Answer it gives u points I think

Explanation:

6 0
2 years ago
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Which of the following describes the term "false information?"
pav-90 [236]
Inaccurate and misleading
3 0
3 years ago
Suppose you have two arrays of ints, arr1 and arr2, each containing ints that are sorted in ascending order. Write a static meth
telo118 [61]
Since both arrays are already sorted, that means that the first int of one of the arrays will be smaller than all the ints that come after it in the same array. We also know that if the first int of arr1 is smaller than the first int of arr2, then by the same logic, the first int of arr1 is smaller than all the ints in arr2 since arr2 is also sorted.

public static int[] merge(int[] arr1, int[] arr2) {
int i = 0; //current index of arr1
int j = 0; //current index of arr2
int[] result = new int[arr1.length+arr2.length]
while(i < arr1.length && j < arr2.length) {
result[i+j] = Math.min(arr1[i], arr2[j]);
if(arr1[i] < arr2[j]) {
i++;
} else {
j++;
}
}
boolean isArr1 = i+1 < arr1.length;
for(int index = isArr1 ? i : j; index < isArr1 ? arr1.length : arr2.length; index++) {
result[i+j+index] = isArr1 ? arr1[index] : arr2[index]
}
return result;
}


So this implementation is kind of confusing, but it's the first way I thought to do it so I ran with it. There is probably an easier way, but that's the beauty of programming.

A quick explanation:

We first loop through the arrays comparing the first elements of each array, adding whichever is the smallest to the result array. Each time we do so, we increment the index value (i or j) for the array that had the smaller number. Now the next time we are comparing the NEXT element in that array to the PREVIOUS element of the other array. We do this until we reach the end of either arr1 or arr2 so that we don't get an out of bounds exception.

The second step in our method is to tack on the remaining integers to the resulting array. We need to do this because when we reach the end of one array, there will still be at least one more integer in the other array. The boolean isArr1 is telling us whether arr1 is the array with leftovers. If so, we loop through the remaining indices of arr1 and add them to the result. Otherwise, we do the same for arr2. All of this is done using ternary operations to determine which array to use, but if we wanted to we could split the code into two for loops using an if statement.


4 0
3 years ago
Number of byte required to store illumination
Rina8888 [55]
If we are talking about light that’s an whole different subject
5 0
3 years ago
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