Given:
In a right triangle, the measure of one acute angle is 12 more than twice the measure of the other acute angle.
To find:
The measures of the 2 acute angles of the triangle.
Solution:
Let x be the measure of one acute angle. Then the measure of another acute is (2x+12).
According to the angle sum property, the sum of all interior angles of a triangle is 180 degrees. So,
Divide both sides by 3.
The measure of one acute angle is 26 degrees. So, the measure of another acute angle is:
Therefore, the measures of two acute angles are 26° and 64° respectively.
Answer:$13 dollars
Step-by-step explanation:
Answer:
1. Add 6 to both sides, cause that is the inverse of subtraction, so you get 5x = 50 as 6 cancels 6 out.
2. Divide 5 from both sides and get x = 10
Answer:
D. 2058.24 in³
Step-by-step explanation:
Let r,h be the radius and height of smaller can and R,H be the radius and height of larger can
Then, R=4r and H=4h
Volume of smaller can=32.16 in³
⇒ πr²h=32.16 in³
Volume of larger can= πR²H
= π(4r²)×4h
= 64πr²h
= 64×32.16 in³
= 2058.24 in³
Hence, correct option is:
D. 2058.24 in³
First you do 3 + 4 + 5 = 12, so there are 12 parts to this ratio.
48 / 12 = 4, this means that each part of the ratio is worth 4 inches.
The longest side is worth 5 parts of the ratio.
4 * 5 = 20 inches
