Question

The rectangle below has an area of 70y⁸ 30y⁶. The width of the rectangle is equal to the greatest common monomial factor of 70y⁸ and 30y⁶. What is the length and width of the rectangle?

Answer 1

Answer:

The Width of the Rectangle =$10y^6$

$\text{Length of the Rectangle}=210y^8$

Step-by-step explanation:

The area of the rectangle $=70y^8 30y^6.$

We are told that the width of the rectangle is equal to the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Let us determine the greatest common monomial factor of $70y^8 \: and\: 30y^6.$

Express each term as a product to pick out the common factors:

$70y^8 =7X10Xy^6Xy^2\\30y^6=3X10Xy^6$

In the two terms, the common terms are 10 and $y^6$. Therefore their greatest monomial factor =$10y^6$

The Width of the Rectangle =$10y^6$

Recall: Area of a Rectangle =Length X Width

$70y^8 30y^6=Length X 10y^6\\Length =70y^8 30y^6 \div 10y^6 \\=\dfrac{70X30Xy^8Xy^6}{10y^6} =210y^8\\\text{Length of the Rectangle}=210y^8$

Answer 2

Answer:

Step-by-step explanation: