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Annette [7]
2 years ago
14

How will the solution of the system y > 2x + Two-thirds and y < 2x + One-third change if the inequality sign on both inequ

alities is reversed to y < 2x + Two-thirds and y > 2x + One-third?
Answer: There is no solution to the system in its original form. There are no points in common. If the signs are reversed, the system has an intersection with an infinite number of solutions.
Mathematics
1 answer:
blagie [28]2 years ago
8 0

Answer:

Step-by-step explanation:344x-5-p-0-9-but=pmc+m2 something like that

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a32 = 7</span>
8 0
4 years ago
Read 2 more answers
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mojhsa [17]

Answer:

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Step-by-step explanation:

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4 years ago
Help pls im strugglin
loris [4]

66 is the correct answer

8 0
4 years ago
HELP!!!.....I’m stressed
yuradex [85]

Answer:

C

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7 0
4 years ago
A study reveals that 65% of homeowners in Omaha own a lawn mower. To test this claim, you form a sample of 500 homeowners in Oma
kotegsom [21]

Answer:

There is no enough evidence to reject the claim using a level of significance of 5%

Step-by-step explanation:

Let p be the true proportion of homeowners in Omaha who own a lawnmower. We want to test  

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We have a large sample of size n = 500 and a point estimate for p is \hat{p}=0.68. The test statistic is given by

Z=\frac{\hat{p}-p_{0}}{\sqrt{p_{0}(1-p_{0})/n}}=\frac{0.68-0.65}{\sqrt{0.65(1-0.65)/500}} where \sqrt{0.65(1-0.65)/500} is the standard error of \hat{p} when H_{0} is true. The observed value is z_{0} = 1.4064 which comes from a standard normal distribution. Because we want to use a level of significance of 5%, our rejection region is RR={z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles respectively. Because 1.4064 does not belong to RR, we fail to reject the null hypothesis.

6 0
3 years ago
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