![\sqrt[3]{a} = {a}^{m} \\ = > { a}^{ \frac{1}{3} } = {a}^{m} \\ = > m = \frac{1}{3}](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Ba%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20%20%7B%20a%7D%5E%7B%20%5Cfrac%7B1%7D%7B3%7D%20%7D%20%20%3D%20%20%7Ba%7D%5E%7Bm%7D%20%20%5C%5C%20%20%3D%20%20%3E%20m%20%3D%20%20%5Cfrac%7B1%7D%7B3%7D%20)
<u>Answer</u><u>:</u>
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Hope you could understand.
If you have any query, feel free to ask.
Answer:
I have no clue
Step-by-step explanation:
1. Search online
2. Never count on me again!
Answer:
Step-by-step explanation:
L=3S
In 5 years,
L+5=2(S+5)
L+5=2S+10
L=2S+5
Substituting from above,
3S=2S+5
S=5
So then,
L=3(5)
L=15
3x - 4y = 9 and 2x + 3y = 7, which of the following would be the best method?
Answer:

Step-by-step explanation:
To find the
we must use the cosine theorem.
The cosine theorem says that:

In this case:



So



