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3 years ago

What is a fraction eqivalent to 5/6

2 answers:

N76 [4]3 years ago

8 0

Answer:Some fraction equivalent to 5/6= 10/12 = 15/18 = 20/24 = 25/30 = 30/36 = 35/42 = 40/48 = 45/54 = 50/60 = 55/66 = 60/72 = 65/78 = 70/84 = 75/90 = 80/96 = 85/102 = 90/108 = 95/114 = 100/120 = 105/126 = 110/132 = 115/138 = 120/144 = 125/150 = 130/156 = 135/162 = 140/168 = 145/174 = 150/180 = 155/186 = 160/192 = 165/198 = 170/204 = 175/210 = 180/216 = 185/222 = 190/228 = 195/234 = 200/240

Step-by-step explanation:

BaLLatris [955]3 years ago

7 0

Answer:

10/12 is an eqivalent fraction to 5/6 hope this helps

Step-by-step explanation:

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solniwko [45]

Answer:

line B'C' = 1

m<C'D'A' = 90 degrees (it is still a rectangle)

Step-by-step explanation:

Dilation of coordinates:

Original: d:(3,2), a:(3,4), b:(7,4), c:(7,2)

Divide all numbers by 2.

Altered: d:(1.5,1), a:(1.5,2), b:(3.5,2), c:(3.5,1)

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3 years ago

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Tems11 [23]

Answer:

1500

Step-by-step explanation:

1200/4=300

1200+300=1500

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3 years ago

Read 2 more answers

One-hundred and forty students are randomly polled at your school about what their favorite lunch food is. The results are organ

VARVARA [1.3K]

Answer:

Step-by-step explanation:

39 because 23 of the students already like hot dogs an 14 like hot dogs and cheeseburgers and 2 like pizza and hot dogs so add them together and you get 39

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3 years ago

Seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Find the probability that (a)

UNO [17]

Answer:

a) P=0.226

b) P=0.6

c) P=0.0008

d) P=0.74

Step-by-step explanation:

We know that the seven balls are randomly withdrawn from an urn that contains 12 red, 16 blue, and 18 green balls. Therefore, we have 46 balls.

a) We calculate the probability that are 3 red, 2 blue, and 2 green balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_3^{12}\cdot C_2^{16}\cdot C_2^{18}=660\cdot 120\cdot 153=12117600$

Therefore, the probability is

$P=\frac{12117600}{53524680}\\\\P=0.226$

b) We calculate the probability that are at least 2 red balls.

We calculate the probability withdrawn of 1 or none of the red balls.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations: for 1 red balls

$C_1^{12}\cdot C_7^{34}=12\cdot 1344904=16138848$

Therefore, the probability is

$P_1=\frac{16138848}{53524680}\\\\P_1=0.3$

We calculate the number of favorable combinations: for none red balls

$C_7^{34}=5379616$

Therefore, the probability is

$P_0=\frac{5379616}{53524680}\\\\P_0=0.1$

Therefore, the the probability that are at least 2 red balls is

$P=1-P_1-P_0\\\\P=1-0.3-0.1\\\\P=0.6$

c) We calculate the probability that are all withdrawn balls are the same color.

We calculate the number of possible combinations:

$C_7^{46}=\frac{46!}{7!(46-7)!}=53524680$

We calculate the number of favorable combinations:

$C_7^{12}+C_7^{16}+C_7^{18}=792+11440+31824=44056$

Therefore, the probability is

$P=\frac{44056}{53524680}\\\\P=0.0008$

d) We calculate the probability that are either exactly 3 red balls or exactly 3 blue balls are withdrawn.

Let X, event that exactly 3 red balls selected.

$P(X)=\frac{C_3^{12}\cdot C_4^{34}}{53524680}=0.57\\$

Let Y, event that exactly 3 blue balls selected.

$P(Y)=\frac{C_3^{16}\cdot C_4^{30}}{53524680}=0.29\\$

We have

$P(X\cap Y)=\frac{18\cdot C_3^{12} C_3^{16}}{53524680}=0.12$

Therefore, we get

$P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\\\P(X\cup Y)=0.57+0.29-0.12\\\\P(X\cup Y)=0.74$

8 0

4 years ago

In the figure below, m angle WXZ=113°, and m angle2 is 3° more then m angle1 Find m angle1

blsea [12.9K]

Answer:

m∠1 = 55° ; m∠2 = 58°

Step-by-step explanation:

Let m∠1 = x° , then m∠2 = x° + 3°

m∠1 + m∠2 = 113°

x° + x° + 3° = 113°

2x + 3 = 113

2x = 110

x = 55°

m∠1 = 55° and m∠2 = 58° 

7 0

3 years ago

What is a fraction eqivalent to 5/6​

What is a fraction eqivalent to 5/6