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stellarik [79]
1 year ago
8

Point Q is on line segment PR . Given PQ=16 and PR=19, determine the length of QR

Mathematics
1 answer:
Nikitich [7]1 year ago
7 0

Answer:

QR = 3

Step-by-step explanation:

given that Q is on the segment PR , then

PQ + QR = PR ( substitute values )

16 + QR = 19 ( subtract 16 from both sides )

QR = 3

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Find the remainder when f(x)=x3−4x2−6x−3 f ( x ) = x 3 − 4 x 2 − 6 x − 3 is divided by x+1
loris [4]

Answer:

The remainder is -2.

Step-by-step explanation:

According to the Polynomial Remainder Theorem, if we divide a polynomial P(x) by a binomial (<em>x</em> - <em>a</em>), then the remainder of the operation will be given by P(a).

Our polynomial is:

P(x) = x^3-4x^2-6x-3

And we want to find the remainder when it's divided by the binomial:

x+1

We can rewrite our divisor as (<em>x</em> - (-1)). Hence, <em>a</em> = -1.

Then by the PRT, the remainder will be:

\displaystyle\begin{aligned}  R &= P(-1)\\ &=(-1)^3-4(-1)^2-6(-1)-3 \\ &= (-1)-4(1)+(6)-3 \\ &= -2 \end{aligned}

The remainder is -2.

5 0
2 years ago
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Dennis_Churaev [7]

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6 0
3 years ago
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Brut [27]
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Vadim26 [7]

Answer:

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Step-by-step explanation:

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7 0
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Hope it helps!
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3 years ago
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