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Nesterboy [21]
2 years ago
7

What is the solution to the equation 1/3 (9x-6)2x=3

Mathematics
1 answer:
jarptica [38.1K]2 years ago
5 0
\frac{1}{3} (9x-6)2x=3 \\ \\ \frac{(9x-6) \times 2x}{3} = 3 \\ \\ \frac{3(3x - 2) \times 2x}{3} = 3 \\ \\ \frac{6x (3x-2)}{3} = 3 \\ \\ 2x(3x-2) = 3 \\ \\ 6x^2 - 4x = 3 \\ \\ 6x^2 - 4x - 3 = 0 \\ \\ x = \frac{4+2 \sqrt{22} }{12} , \frac{2- \sqrt{22} }{12} \\ \\ x = \frac{2+ \sqrt{22} }{6} , \frac{2- \sqrt{22} }{6}
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Answer:

Let s = students

Let a = adults

2s + 4a = 2800

Step-by-step explanation:

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What is -19 equal to
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Answer:

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Step-by-step explanation:

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2 years ago
Lightbulbs of a certain type are advertised as having an average lifetime of 750 hours. The price of these bulbs is very favorab
Katyanochek1 [597]

Answer:

(a) Customer will not purchase the light bulbs at significance level of 0.05

(b) Customer will purchase the light bulbs at significance level of 0.01 .

Step-by-step explanation:

We are given that Light bulbs of a certain type are advertised as having an average lifetime of 750 hours. A random sample of 50 bulbs was selected,  and the following information obtained:

Average lifetime = 738.44 hours and a standard deviation of lifetimes = 38.2 hours.

Let Null hypothesis, H_0 : \mu = 750 {means that the true average lifetime is same as what is advertised}

Alternate Hypothesis, H_1 : \mu < 750 {means that the true average lifetime is smaller than what is advertised}

Now, the test statistics is given by;

       T.S. = \frac{Xbar-\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, X bar = sample mean = 738.44 hours

               s  = sample standard deviation = 38.2 hours

               n = sample size = 50

So, test statistics = \frac{738.44-750}{\frac{38.2}{\sqrt{50} } } ~ t_4_9

                            = -2.14

(a) Now, at 5% significance level, t table gives critical value of -1.6768 at 49 degree of freedom. Since our test statistics is less than the critical value of t, so which means our test statistics will lie in the rejection region and we have sufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is smaller than what is advertised and so consumer will not purchase the light bulbs.

(b) Now, at 1% significance level, t table gives critical value of -2.405 at 49 degree of freedom. Since our test statistics is higher than the critical value of t, so which means our test statistics will not lie in the rejection region and we have insufficient evidence to reject null hypothesis.

Therefore, we conclude that the true average lifetime is same as what it has been advertised and so consumer will purchase the light bulbs.

6 0
3 years ago
Solve Quadratic Equations by Factoring:
mr_godi [17]

Answer:

  1. x = 0 or 1
  2. x = ±i/4
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Step-by-step explanation:

Factoring is aided by having the equations in standard form. The first step in each case is to put the equations in that form. The zero product property tells you that a product is zero when a factor is zero. The solutions are the values of x that make the factors zero.

1. x^2 -x = 0

  x(x -1) = 0 . . . . . x = 0 or 1

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2. 16x^2 +1 = 0

This is the "difference of squares" ...

  (4x)^2 - (i)^2 = 0

  (4x -i)(4x +i) = 0 . . . . . x = -i/4 or i/4 (zeros are complex)

__

3. x^2 +10x +25 = 0

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5 0
3 years ago
What is the answer to this problem?
Andrei [34K]

i think the best answer for this question is A)

5 0
3 years ago
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