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tester [92]
1 year ago
15

Question 1

Mathematics
1 answer:
Oksi-84 [34.3K]1 year ago
6 0

Answer: 17.2

Step-by-step explanation:

By the Pythagorean theorem,

10^{2}+14^{2}=(AC)^{2}\\\\(AC)^{2}=296\\\\AC=\sqrt{296} \approx \boxed{17.2}

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16.6

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Given g(x)=-2x-3, then what is g(2m+7)
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Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

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