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2 years ago

I WILL MARK BRAINIEST

Mathematics

1 answer:

yan [13]2 years ago

5 0

Answer:

x=20

Step-by-step explanation:

7x+2x=180(being straight angle )

9x=180

x=180/9

x=20

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You weld two piece's of steel together. The toral thickness is 33/64 inch. If one piece of steel is 9/32 inch thick, how thick t

Anon25 [30]

Subtract the thickness of the known piece from the total thickness.

Because they have different denominators rewrite them to have the same.

9/32 x 2 = 18/64

Now you have 33/64 - 18/64 = 15/64

The other piece is 15/64 inch thick.

4 0

2 years ago

Solving Rational equations. LCD method. Show work. Image attached.

Dmitry [639]

Answer:

$b=1$

Step-by-step explanation:

The given rational equation is

$\frac{2b-5}{b-2} -2=\frac{3}{b+2}$

The Least Common Denominator is $(b+2)(b-2)$ .

Multiply each term in the equation by the LCD.

$(b+2)(b-2)\times \frac{2b-5}{b-2} -(b+2)(b-2)\times2=(b+2)(b-2)\times\frac{3}{b+2}$

Simplify;

$(b+2)\times \frac{2b-5}{1} -2(b+2)(b-2)=(b-2)\times\frac{3}{1}$

$(b+2)(2b-5) -2(b+2)(b-2)=3(b-2)$

Expand and group similar terms

$2b^2-5b+4b-10 -2(b^2-4)=3b-6$

$2b^2-5b+4b-10 -2b^2+8=3b-6$

$-b-2=3b-6$

$3b+b=-2+6$

$4b=4$

$b=1$

3 0

2 years ago

Write the equation -4x^2+9y^2+32x+36y-64=0 in standard form. Please show me each step of the process!

IgorC [24]

Hey there, hope I can help!

$-4x^2+9y^2+32x+36y-64=0$

$\mathrm{Add\:}64\mathrm{\:to\:both\:sides} \ \textgreater \ 9y^2+32x+36y-4x^2=64$

$\mathrm{Factor\:out\:coefficient\:of\:square\:terms} \ \textgreater \ -4\left(x^2-8x\right)+9\left(y^2+4y\right)=64$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}4$
$-\left(x^2-8x\right)+\frac{9}{4}\left(y^2+4y\right)=16$

$\mathrm{Divide\:by\:coefficient\:of\:square\:terms:\:}9$
$-\frac{1}{9}\left(x^2-8x\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}$

$\mathrm{Convert}\:x\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x^2-8x+16\right)+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)$

$\mathrm{Convert}\:y\:\mathrm{to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y^2+4y+4\right)=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Convert\:to\:square\:form}$
$-\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right)$

$\mathrm{Refine\:}\frac{16}{9}-\frac{1}{9}\left(16\right)+\frac{1}{4}\left(4\right) \ \textgreater \ -\frac{1}{9}\left(x-4\right)^2+\frac{1}{4}\left(y+2\right)^2=1$

$Refine\;once\;more\;-\frac{\left(x-4\right)^2}{9}+\frac{\left(y+2\right)^2}{4}=1$

For me I used
$\frac{\left(y-k\right)^2}{a^2}-\frac{\left(x-h\right)^2}{b^2}= 1$
$As\;\mathrm{it\;\:is\:the\:standard\:equation\:for\:an\:up-down\:facing\:hyperbola}$

I know yours is an equation which is why I did not go any further because this is the standard form you are looking for. I would rewrite mine to get my hyperbola standard form. However the one I have provided is the form you need where mine would be.
$\frac{\left(y-\left(-2\right)\right)^2}{2^2}-\frac{\left(x-4\right)^2}{3^2}=1$

Hope this helps!

4 0

3 years ago

Please answer<br> *Will give brainliest*<br> PLEASE DO NOT EXPLAIN

seraphim [82]

Answer:

a, c, c, d, c, c.

Step-by-step explanation:

I worked out the math

3 0

2 years ago

The density d kg/m3 of a cube of mass m kilograms and side length x meters is given by the formula: What is the value of d if

bearhunter [10]

Answer:

5000kg/m3

Step-by-step explanation:

Its easy to get the answer of a question from the unit.

So, it will be mass over metre cube.

Therefore, m=40kg x= (0. 2)^3 =0. 008m

40/0. 008 = 5000kg/m^3

6 0

2 years ago