If you distribute -4 through (5k-7), it equals -20k + 28. Then put on the other -2k on that side of the equals sign and you should have -22k + 28 = -2(9k+5) Then you need to distribute -2 through (9k+5) which equals -18k - 10. You then should have -22k+28=-18k-10. Add 22k to both sides to cancel it out, then you should have 28=4k-10. Add 10 to both sides to get the 4k by itself, which will be 38=4k, then divide both sides by 4 to get k by itself. 38/4 = 19/2. k = 19/2
Answer:
look at the pictures
Step-by-step explanation:
HOPE THIS helps
The 'x' in x^2-7x-30=0 is 4.
Answer:x=-2
Step-by-step explanation:
3 x -2^2
3 x -4 = -12
You could rewrite
![F(x)](https://tex.z-dn.net/?f=F%28x%29)
as
![\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%5E2%2B3x%2B2%7D%7Bx%5E2%2B5x%2B4%7D%3D%5Cdfrac%7B%28x%2B1%29%28x%2B2%29%7D%7B%28x%2B1%29%28x%2B4%29%7D)
and be tempted to cancel out the factors of
![x+1](https://tex.z-dn.net/?f=x%2B1)
. But this cancellation is only valid when
![x\neq-1](https://tex.z-dn.net/?f=x%5Cneq-1)
.
When
![x=-1](https://tex.z-dn.net/?f=x%3D-1)
, you end up with the indeterminate form
![\dfrac00](https://tex.z-dn.net/?f=%5Cdfrac00)
, which is why
![-1](https://tex.z-dn.net/?f=-1)
is not a zero.