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2 years ago

Which expression uses the associative property to make it easier to evaluate 14(3/2 x 1/4)

Mathematics

2 answers:

Olin [163]2 years ago

8 0

Answer: 5 1/4

Step-by-step explanation:

No need

Sav [38]2 years ago

6 0

Answer:

Not sure but the answer to 14(3/2 x 1/4) is 5.25

Step-by-step explanation:

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Write the slope-intercept form of an equation for the line that passes through (2, 3) and is parallel to the graph of y = 2x -1

ehidna [41]

Answer:

Step-by-step explanation:

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3 years ago

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A mallard duck is 56 to 65 cm long if the duck travel 97.8 miles at top speed in 1.5 hours how far did it travel in 1 hour

ra1l [238]

Answer:

They traveled 2.71 in 1 hr

Step-by-step explanation:

97.8 divided by 1.5 then multiply that by 1hr

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2 years ago

The equation y = 7x+25 gives the number of minutes it takes to prepare a meal y given the number of people being served x. Which

klemol [59]

Answer- C. For every extra person served, the time it takes to prepare a meal increases by 7 minutes.

Solution-

y = 7x+25

Where y = the number of minutes it takes to prepare a meal

x = the number of people being served.

If the number of persons increased by one, so x' = (x+1)

Then y' = 7x' + 25 = 7(x+1) + 25 = 7x + 7 + 25 = 7x + 25 + 7 = y + 7

∴ As y gets increased by 7 for every 1 more person , so C is the correct answer.

8 0

3 years ago

Please help I really need help on this I would really appreciate it anything helps !

andreev551 [17]

Answer:

AXE and CXD are vertical angles

AXF and FXD are supplementary angles

DXC and BXC are complementary angles

EXA and AXB are adjacent angles

AXC and CXD are supplementary angles

EXD and AXC are vertical angles

Step-by-step explanation:

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2 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

2 years ago