If you have 3 trillion dollars and a cop charges you 20,000 how much do you have left

Solve each equation 11.3 - 7.2f = -3.82

Tema [17]

11.3-7.2f = -3.82
-11.3 -11.30
_____________
-7.2f = -15.12
____ _____
-7.2 -7.2
f = 2.1

6 0

3 years ago

You make a time capsule with your friends. Find the surface area of the shape pictured. Use 3.14 to approximate pi.

Orlov [11]

Answer: $1,475.8mm^{2}$

Step-by-step explanation:

1. If you join the top part and the bottom part of the figure, you obtain a sphere. Then, you must apply the formula for calculate the surface area of a sphere:

$SA_s=4r^{2}(3.14)$

Where r is the radius ( $r=\frac{10mm}{2}=5mm$ )

2. Then:

$SA_s=4(5mm)^{2}(3.14)=314mm^{2}$

3. The formula for calculate the suface area of the red part, which is a cylinder, is:

$SA_c=2(3.14)(r)(h)$

Where h is the height (h=32mm)

4. Then:

$SA_c=2(3.14)(5mm)(32mm)=1,004.8mm^{2}$

5. So, the total surface area is:

$SA_t=314mm^{2}+1,004.8mm^{2}=1,318.8mm^{2}$

6 0

3 years ago

H=−4.9t2+25t

lina2011 [118]

ANSWER

5

EXPLANATION

The equation that expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground is

$h(t) = - 4.9 {t}^{2} + 25t$

To find the time when the ball hit the ground,we equate the function to zero.

$- 4.9 {t}^{2} + 25t = 0$

Factor to obtain;

$t( - 4.9t + 25) = 0$

Apply the zero product property to obtain,

$t = 0 \: or \: \: - 4.9t + 25 = 0$

$t = 0 \: \: or \: \: t = \frac{ - 25}{ - 4.9}$

t=0 or t=5.1 to the nearest tenth.

Therefore the ball hits the ground after approximately 5 seconds.

4 0

2 years ago

Read 2 more answers

the length of a rectangle is 8cm more than the width and its area is 172cm2 .find the width of the rectabgle

nikdorinn [45]

$l-the\ length\\l+8-the\ width\\A=172\ cm^2\\\\A=lengtf\cdot width\\\\subtitute\\\\l(l+8)=172\\\\l^2+8l=172\ \ \ |subtract\ 172\ from\ both\ sides\\\\l^2+8l-172=0\\a=1;\ b=8;\ c=-172\\\\\Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot(-172)=64+688=752 > 0\\\\l_1=\dfrac{-b-\sqrt\Delta}{2a}\ and\ l_2=\dfrac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{752}=\sqrt{16\cdot47}=4\sqrt{47}\\\\l_1=\dfrac{-8-4\sqrt{47}}{2\cdot1}=-4-2\sqrt{47} < 0\\\\l_2=\dfrac{-8+4\sqrt{47}}{2\cdot1}=-4+2\sqrt{47} > 0\\\\The\ width:l+8=-4+2\sqrt{47}+8=4+2\sqrt{47}\\\\Answer:\boxed{length=(2\sqrt{47}-4)cm;\ width=(4+2\sqrt{47})cm}$
$length\approx9.71cm;\ width\approx17.71cm$

4 0

3 years ago

I need help! Will mark Brainliest for full answer!!!

Softa [21]

Answer:

Part a .............> x = 11

Part b .............> k = 57.2

Part c .............> y = 9.2

Explanation:

The three problems deal with inverse variation between two variables

An inverse variation relation between two variables means that when one of the variables increases, the other will decrease (and vice versa)

Mathematically, an inverse variation relation is represented as follows:

$y = \frac{k}{x}$

where x and y are the two variables and k is the constant of variation

Now, let's check the givens:

Part a:

We are given that y = 3 and k = 33

Substitute in the original relation and solve for x as follows:

$y = \frac{k}{x}\\ \\3 = \frac{33}{x}\\ \\x=\frac{33}{3}=11$

Part b:

We are given that y = 11 and x = 5.2

Substitute in the original relation and solve for k as follows:

$y=\frac{k}{x}\\ \\11=\frac{k}{5.2}\\ \\k=11*5.2=57.2$

Part c:

We are given that x=7.8 and k=72

Substitute in the original relation and solve for y as follows:

$y=\frac{k}{x}=\frac{72}{7.8}=9.2$ to the nearest tenth

Hope this helps :)

6 0

2 years ago