If you have 3 trillion dollars and a cop charges you 20,000 how much do you have left

Kendra owns a restaurant. She charges $3.00 for two eggs and one piece of toast and $1.80 for one egg and one piece of toast. Ho

Shkiper50 [21]

Lets t = # pieces of toast
e = # of eggs

2e + t = 3
e + t = 1.8
----------------subtract
e = 1.2
t = 1.8 - e
t = 1.8 - 1.2
t = 0.6

answer
Kendra charges $1.2 per egg and 60 cents per toast

5 0

3 years ago

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Iris is a saleswoman whose base pay plus commissions amounted to $69,464 last year. If her base pay was $39,710 and she made $78

Murljashka [212]

Iris is a saleswoman whose base pay plus commissions amounted to $69,464 last year. If her base pay was $39,710 and she made $78,300 in sales last year,
what was her rate of commission? 
Commissions were $29,590 against sales of $78,300 
Her rate of commission was 37.79%

6 0

4 years ago

I need help with this

gladu [14]

Answer:

-25

Step-by-step explanation:

You can round -98.5 to 100

Then round 3.8 to 4

Negative divided by positive is negative.

-100 ÷ 4 = -25

8 0

4 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the critical points.

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

3 years ago

What is the solution to the following system of equations?

Damm [24]

Answer:

(3, - 1 )

Step-by-step explanation:

Given the 2 equations

x - 3y = 6 → (1)

2x + 2y = 4 → (2)

Rearrange (1) expressing x in terms of y by adding 3y to both sides

x = 6 + 3y → (3)

Substitute x = 6 + 3y into (2)

2(6 + 3y) + 2y = 4 ← distribute and simplify left side

12 + 6y + 2y = 4

12 + 8y = 4 ( subtract 12 from both sides )

8y = - 8 ( divide both sides by 8 )

y = - 1

Substitute y = - 1 into (3) for corresponding value of x

x = 6 + 3(- 1) = 6 - 3 = 3

Solution is (3, - 1 )

6 0

3 years ago

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