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jeka57 [31]
2 years ago
14

Pythagorean theorem. How do I solve this?

Mathematics
2 answers:
anyanavicka [17]2 years ago
7 0

Answer:

By using the pythsgorean theorem! simple

IrinaK [193]2 years ago
7 0

Answer:\sqrt{155}

Step-by-step explanation:

Oh god pythagorean triples got thrown out the window for this one. This will be a bit ugly.

First, we find the other side length of the rectangle using the pythagorean theorem.

Then, we use that side length in ANOTHER pythagorean theorem to get our answer.

Well, we know that the side length is \sqrt{5^{2}+9^{2} }

We'll use whatever that number is, let's call it x for now, in our other expression:

\sqrt{x^{2}+7^{2}}

So we can do this in one clean equation by substituting our first equation as x in the second one.

Or do them separately. Your choice.

Anyways, try to solve this one now that you know what to do. If you need more help then message.

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Read 2 more answers
Lena is 10 years old. She asks her dad how old he is. He tells her that the lowest common multiple of their ages is 14 times the
Ksju [112]

Answer:

  35

Step-by-step explanation:

We know the factors of Lena's age are 2 and 5. The least common multiple must have these factors and the factors of 14, so will at least have factors of 2, 5, and 7.

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___

The GCF is 5; the LCM is 70 = 5×14.

_____

Sometimes, I use a little 3-part diagram to think about LCM and GCF. Here, it would look like ...

  (2 [5) 7]

where the numbers in curved brackets (2·5) and the numbers in square brackets [5·7] are factors of the two numbers of concern (Lena's age, her dad's age). The middle number in both brackets [5) is the greatest common factor, and the product of all three numbers is their least common multiple.

Here, the product of outside numbers, 2·7 = 14, represents the ratio of the LCM to the GCF. We know that Lena's age has factors of only 2 and 5, so the numbers in the diagram have to be (2[5)7], where 2 and 7 are on the ends and 5 is in the middle.

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3 years ago
the diagram gives the dimensions of a swimming pool.if a cover is needee for the pool, what will be the approximate area of the
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820 - W = 620
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