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erica [24]
2 years ago
9

170 is one tenth of 17 true or false

Mathematics
2 answers:
Lubov Fominskaja [6]2 years ago
3 0
No 170 is not one tenth of 17. 17 is one tenth of 170. So the answer is false.
zubka84 [21]2 years ago
3 0
The answers is false! Hope this helps!
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2:20PM

Step-by-step explanation:

3:45 - 1 hour = 2:45 (drive)

2:45 - 25 minutes = 2:20

2:20pm

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3/4x+3-2x= -1/4+1/2x+5<br> What is the value of x
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Step-by-step explanation:

3/4x+3-2x=1/4+1/2x+5

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Give an example question ( use words and numbers)
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A 2 - - 7 = 9
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3 years ago
Which of the following is one way the expressionZ n can be rewritten using summation properties?181 46(47)2 T 21 64(65)1 (64 (65
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5 0
3 years ago
Solve the quadratic equation by using a graphic approach. Round your answer to the hundredths place.
den301095 [7]

Answer:

x = 3.24, x = -1.24

Step-by-step explanation:

The standard form for a quadratic equation is ax^2+bx+c=0. For your equation a = 1, b = -2, c = -4. The quadratic formula you will be using is x=\frac{-b\pm \sqrt{b^{2} -4ac} }{2a}.

Plug in a = 1, b = -2, and c = -4 into the formula.

=\frac{-\left(-2\right)\pm \sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}}{2\cdot \:1}

We'll do the top part first:

\sqrt{\left(-2\right)^2-4\cdot \:1\cdot \left(-4\right)}

Apply rule - (-a) = a

=\sqrt{\left(-2\right)^2+4\cdot \:1\cdot \:4}

Apply exponent rule (-a)^{n} =a^n if n is even

(-2)^2=2^2

=\sqrt{2^2+4\cdot \:1\cdot \:4}

Multiply the numbers

=\sqrt{2^2+16}

2^2=4

=\sqrt{4+16}

Add

=\sqrt{20}

The prime factorization of 20 is 2^2*5

20 divides by 2. <em>20 = 10 * 2</em>

<em />=2*10<em />

10 divides by 2. <em>10 = 5 * 2</em>

<em />=2* \:2*5<em />

2 & 5 are prime numbers so you don't need to factor them anymore

=2*2*5

=2^2*5

=\sqrt{2^2\cdot \:5}

Apply radical rule \sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}

=\sqrt{5}\sqrt{2^2}

Apply radical rule \sqrt[n]{a^{n} } =a; \sqrt{2^2} =2

=2\sqrt{5}

=\frac{-\left(-2\right)\pm \:2\sqrt{5}}{2\cdot \:1}

Because of the \pm you have to separate the solutions so that one is positive and the other is negative.

x=\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1},\:x=\frac{-\left(-2\right)-2\sqrt{5}}{2\cdot \:1}

Positive x:

\frac{-\left(-2\right)+2\sqrt{5}}{2\cdot \:1}

Apply rule -(-a)=a

=\frac{2+2\sqrt{5}}{2\cdot \:1}

Multiply

=\frac{2+2\sqrt{5}}{2}

Factor 2+2\sqrt{5} and rewrite it as =2\cdot \:1+2\sqrt{5}. Factor out 2 because it is the common term. =2\left(1+\sqrt{5}\right).

=\frac{2\left(1+\sqrt{5}\right)}{2}

Divide 2 by 2

x=1+\sqrt{5} or x=3.24 (You'll probably have to use a calculator for the square root of 5)

^Repeating the process of positive x for negative x in order to get x=1-\sqrt{5} or x=-1.24

4 0
2 years ago
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