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2 years ago

You roll a number cube. What is the probability it will land on a number greater than 5?

1 answer:

5 0

1 out of 6 chances

Explanation: there’s 6 sides of a cube if you mark them 1-6 there only one side that you can land on that is greater then 5 which is six also if you need it in percent it’s 16.6%

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2 years ago

$16 is to 116.1 as what amount is to 178.4 ?

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3 years ago

Find exact values for sin θ, cos θ and tan θ if csc θ = 3/2 and cos θ < 0.

kumpel [21]

Answer:

Part 1) $sin(\theta)=\frac{2}{3}$

Par 2) $cos(\theta)=-\frac{\sqrt{5}}{3}$

Part 3) $tan(\theta)=-\frac{2\sqrt{5}}{5}$

Step-by-step explanation:

step 1

Find the $sin(\theta)$

we have

$csc(\theta)=\frac{3}{2}$

Remember that

$csc(\theta)=\frac{1}{sin(\theta)}$

therefore

$sin(\theta)=\frac{2}{3}$

step 2

Find the $cos(\theta)$

we know that

$sin^{2}(\theta) +cos^{2}(\theta)=1$

we have

$sin(\theta)=\frac{2}{3}$

substitute

$(\frac{2}{3})^{2} +cos^{2}(\theta)=1$

$\frac{4}{9} +cos^{2}(\theta)=1$

$cos^{2}(\theta)=1-\frac{4}{9}$

$cos^{2}(\theta)=\frac{5}{9}$

square root both sides

$cos(\theta)=\pm\frac{\sqrt{5}}{3}$

we have that

$cos(\theta) < 0$ ---> given problem

$cos(\theta)=-\frac{\sqrt{5}}{3}$

step 3

Find the $tan(\theta)$

we know that

$tan(\theta)=\frac{sin(\theta)}{cos(\theta)}$

we have

$sin(\theta)=\frac{2}{3}$

$cos(\theta)=-\frac{\sqrt{5}}{3}$

substitute

$tan(\theta)=\frac{2}{3}:-\frac{\sqrt{5}}{3}=-\frac{2}{\sqrt{5}}$

Simplify

$tan(\theta)=-\frac{2\sqrt{5}}{5}$

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2 years ago

5x+7y=10 into slope form

marysya [2.9K]

The answer is y=10/7-5/7x, subtract the 5x and put it on the other side then divide the 7 from the y and divide it to 10-5x to get the answer.

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3 years ago

Please help me this is urgent.!

nata0808 [166]

V= 3.14• 5^2•4
V= 3.14 •25•4
V= 78.5•4
V=314

Sorry I couldn’t give a more detailed explanation but here is the original equation for volume of a cylinder:

V=πr2h

Hope this helps comment below for more questions :)

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3 years ago

Read 2 more answers