The answer is B. He is incorrect because he should have only 5 factors of 3.
I believe the answer is -25/6 :)
After a little manipulation, the given diff'l equation will look like this:
e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2
Now let x=0 and y = 1, o find c:
e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.
Answer: Once
Step-by-step explanation: If you do 100 - 10 you get 90 as result, therefore you don't have 100 anymore making the only logical answer to this "ONCE".
