Answer:
x=2
Step-by-step explanation:
logx (2x)^3 = 6
We can rewrite without the exponent
3 logx (2x) = 6
Divide by 3
3/3 logx (2x) = 6/3
logx (2x) = 2
Raise each side to the base x
x^ logx (2x) =x^ 2
2x = x^2
Subtract 2x from each side
2x-2x = x^2 -2x
0 = x^2 -2x
Factor an x
0 = x(x-2)
Using the zero product property
x =0 x-2 =0
x =0 x=2
We cannot have a base of 0, so x cannot equal 0
x=2
3x - 4 + 1 = -2x - 5 + 5x
First, simplify 3x - 4 + 1 to 3x - 3. / Your problem should look like: 3x - 3 = -3x - 5 + 5x
Second, simplify -2x - 5 + 5x to 3x - 5. / Your problem should look like: 3x - 3 = 3x - 5
Third, cancel 3x on both sides. / Your problem should look like: -3 = -5
Fourth, since -3 = -5 is false, there is no solution.
Answer: No solution
Answer:
a:
-4 + (-7)
b:
-4+7
Step-by-step explanation:
here sorry it took so long
I belive the answer would be B if not im sorry
Answer:
I don't know but if you figure it out tell me. Thanks
Step-by-step explanation:
