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MA_775_DIABLO [31]
2 years ago
8

Which is the correct graph for the inequality

Mathematics
1 answer:
eduard2 years ago
6 0
The correct answer is graph B
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scientists are studying the temperature on a distant planet. they find that the surface temperature at one location is 45° celsi
tia_tia [17]

Answer:

T=45-5H

Step-by-step explanation:

4 0
3 years ago
What is the volume of the following triangular prism?
sergiy2304 [10]

Answer:

<h2>288 ft³</h2>

Step-by-step explanation:

The formula of a volume of a prism:

V=BH

where

<em>B</em><em> - area of a base</em>

<em>H</em><em> - height of a prism</em>

<em />

In the base we have the right treiangle. The formula of an area of a right triangle is:

A=\dfrac{ab}{2}

where

<em>a, b</em><em> - are legs</em>

We have

a=6\ ft,\ b=8\ ft

Substitute:

B=\dfrac{(6)(8)}{2}=\dfrac{48}{2}=24\ ft^2

Calculate the volume.

Substitute

B=24\ ft^2,\ H=12\ ft

V=(24)(12)=288\ ft^3

3 0
3 years ago
There are 144 animals at a pet store. 56 are cats; the rest are dogs. what fraction of all of the animals are dogs?
svlad2 [7]
144 - 56 = 88

88/144 simplified to -----> 11/18
4 0
4 years ago
Read 2 more answers
If f(x) = 4 – x2 and g(x) = 6x, which expression is equivalent to (9-1(3)?
Anni [7]

Answer:

( g − f ) ( 3 ) = 23

Step-by-step explanation:

(g-f)(x)=g(x)-f(x)

=6x-(4-X(2))

=x(2)+6x-4

to evaluate (g-f) (#) substitute x=3 into (g-f)(x)

(g-f)=(9)+(6 x 3) -4=23

8 0
4 years ago
What is the approximate radius of the bowl shown that is shaped as a hemisphere
wolverine [178]

Answer:

Approximate radius of the given hemisphere is 3 in.

Step-by-step explanation:

Formula to calculate the volume of a hemisphere is given by,

V = \frac{2}{3}\pi r^{3}

Since, volume of the given hemisphere in the picture = 56.52 in²

By substituting the value of V in the formula,

56.52 = \frac{2}{3}\pi r^{3}

Now solve the expression for the value of 'r',

r³ = \frac{3}{2\pi }(56.52)

r³ = 26.99

r = ∛(26.99)

r = 3 in.

Therefore, approximate radius of the given hemisphere is 3 in.

5 0
3 years ago
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