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Tema [17]
4 years ago
7

Jaquan mixed 1 3/4 teaspoons of baking powder with 1 1/2 cups of flour to make a cake. Jasmine asked him to make some cake for h

er birthday party. To make a cake the birthday cake, Jaquan used exactly 9 cups of flour. How many teaspoons of baking powder should Jaquan use to make a birthday cake?
Mathematics
1 answer:
Vlada [557]4 years ago
8 0

Answer:

10¹/₂ of flour

Step-by-step explanation:

Jaquan mixed 1 ³/₄ teaspoons of baking powder with 1 ¹/₂ cups of flour to make a cake

which means

1 ³/₄ + 1 ¹/₂ = 2³⁺²/₄ = 2⁵/₄

⁵/₄ = 1¹/₄

adding ⁵/₄ to 2 = 1¹/₄ + 2 = 3¹/₄ to make cake

but to find the teaspoons of baking powder that Jaquan will use to make a birthday cake in the same ratio if Jaquan used exactly 9 cups of flour

we need to express it in ratio and

1 ³/₄ is baking powder

1 ¹/₂ is flour

x is the other baking powder we are looking for

9 is for flour

1 ³/₄ : 1 ¹/₂ = x:9

converting to whole improper fraction

1 ³/₄ = 4x1+3/4 = 4+3/4 = 7/4

1 ¹/₂ = 2x1+1/2 = 2+1/2 = 3/2

7/4:3/2 = x:9

7/4/3/2 = 7/4 x 2/3 = 7x1/2x3 = 7/6

7/6 = x/9

cross multiply

7x9 = 6x

63 = 6x

x = 63/6 = 21/2 = 10¹/₂ of flour

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How many sixteenths are there in 5/8​
nadya68 [22]

Answer:

10!

Step-by-step explanation:

Exuse me if im wrong :')

6 0
3 years ago
Name a pair of fractions that use the least common denominator and are equivalent to 9/10 + 5/6
grin007 [14]
The smallest common denominator is 30 in so 
<span>9/10=27/30 and 5/6=25/30 are your answers ; ]</span>
6 0
3 years ago
Read 2 more answers
I. Daska is situated at a distance of 15 miles from both Gujranwala and Sialkot. A bus travels from Gujranwala to Daska at an av
son4ous [18]

Answer:

The average speed of the entire trip is 8.5 miles per hour.

Step-by-step explanation:

Speed = Total  Distance / Total Time

So we have to find the total distance and the total time taken .

1) From Gujranwala to Daska

speed= 25miles/hour           distance = 15miles

Time taken = distance / speed

                   = 15/25= 0.6 hours

2)  From Daska to Sialkot

speed= 40miles/hour           distance = 15miles

Time taken = distance / speed

                   = 40/15= 2.67 hours

3 ) From  Sialkot to Daska

speed= 30miles/hour           distance = 15miles

Time taken = distance / speed

                   = 30/15= 2 hours

The total distance traveled to three places is = 15+ 15+15= 45miles

The Total time taken is = 0.6+ 2.67+ 2= 5.267=5.3 hours

Speed = Total  Distance / Total Time

Speed= 45/ 5.3

          = 8.49=8.5 miles per hour

The average speed of the entire trip is 8.5 miles per hour.

7 0
3 years ago
Please help me and show your wprk
stellarik [79]
This is how I find the GCF.

I find the prime factors. 

63/3 = 21
21/3 = 7
7/7 = 1 

81/3 = 27
27/3 = 9
9/3 = 3
3/3 = 1

Then I find the common prime factors:
63: 3 x 3 x 7
81: 3 x 3 x 3 x 3 

Then I multiply the common prime factors:
3 x 3 = 9

The GCF for 63 and 81 (number 3) is 9. 

I bet you can use this method for all the other GCFs! :)

For this one, find the prime factors like before, and if there aren't any besides one, then it's a prime number. 

75/3 = 25
25/5 = 5
5/5 = 1
 
The prime factorization for 75 is 3 x 5 x 5

(I don't know the answer to 7, 8, 9, 10, 11, 12, 25, or 26, sorry!)


3 0
4 years ago
Three valid names for an octagon
netineya [11]
Remmeber that an octagon is a polygon formed by chain of 8 straight line segments.

The first valid name for a polygon of eight sides is octagon (from greek oktagonon, which means eight angles) 

The second valid name for a polygon of eight sides is eight-sided polygon.

The third valid name of a polygon of eight sides is 8-gon. After 6 sides, mathematicians usually refer to these polygons as n-gons, so an eight-sided polygon will be an 8-gon.

We can conclude that the three valid names for an octagon are: octagon, eight-sided polygon, and 8-gon.
7 0
3 years ago
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