How many solutions does the equation below have? 1/(-6-8x) = -3- 1x

Mathematics

1 answer:

uranmaximum [27]1 year ago

5 0

Answer:

This equation has 2 solutions.

1. $x=\frac{-15+\sqrt{89}}{8}$

2. $x=-\frac{15+\sqrt{89}}{8}$

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1/2(2+a)=3a+4/3 solve it

Mumz [18]

1/2(2+a)=3a+4/3

first, you use the distributive property

then your problem changes to...

1 + 1/2a = 3a + 4/3

then you subtract 1/2a with 3a

1 = 2 1/2a +4/3

now you subtract 1 with 4/3

-1/3 = 2 1/2a

now you divide -1/3 with 2 1/2a

-2/15 = a

A = -2/15 is your answer. Hope this helps :)

4 0

3 years ago

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the 9th month
 $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: B. −11.63 dollars per month.