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Nadusha1986 [10]
2 years ago
7

What is the approximate solution to this equation? 15(3)^2x=90

Mathematics
1 answer:
mel-nik [20]2 years ago
7 0

Answer:

x ≈ 0.67

Step-by-step explanation:

15(3)^2x = 90\\\\15(9)x = 90\\\\135x = 90\\\\x = 90/135\\\\ x = 2/3\\\\x = 0.666...\\\\x = 0.67 \ (rounded \ to \ nearest \ hundredth )

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Answer:

Step-by-step explanation:

Given is a parabola

y=-14x^2-2x-2

Let us rewrite this in vertex form

y=-14(x+\frac{1}{14})^2-\frac{27}{14}

Hence vertex =(\frac{-1}{14} ,\frac{-27}{14} )

Axis of symmetry is

x=-\frac{1}{14}

a=\frac{1}{(14)4} =\frac{1}{56}

Hence focus would lie on the line of symmetry at a distance of a from vertex

So focus =(-\frac{1}{14} ,-\frac{27}{14} -\frac{1}{56} )\\=(-\frac{1}{14} , -\frac{109}{56} )

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3 years ago
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X+3y=10<br>X-5y=-2<br><br>X=? <br>Y=?
Inessa [10]
<span>X+3y=10
X-5y=-2
--------------subtract
8y = 12
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</span><span>X+3y=10
x = 10 - 3y
x = 10 - 3(1.5)
x = 10 - 4.5
x = 5.5

answer
x = 5.5 and y = 1.5 </span>
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