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Marta_Voda [28]
3 years ago
5

How do you solve |2b-5| + 1?

Mathematics
1 answer:
Sveta_85 [38]3 years ago
6 0
FIRST STEP- (2b-5)+1 Remove parenthesis . 2nd Step: 2b-5+1 Calcute Third Step: 2b-4 Factor the expression Answer // 2(b-2).
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Simplify (4xy^-2)/(12x^(-1/3)y^-5) and Show work ...?
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The answer is \frac{x^{4/3}y^{3}}{3}.

The fraction is: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5}  }
Let's rewrite it: \frac{4xy^{-2} }{12 x^{-1/3} y^{-5} }=\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }

Since \frac{x^{a} }{x^{b}} =x^{a-b},
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*** \frac{x}{ x^{-1/3} }= x^{1-(-1/3)} = x^{3/3+1/3} = x^{4/3}
*** \frac{y^{-2} }{ y^{-5} }=  y^{-2-(-5)} = y^{-2+5} = y^{3}
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\frac{4 }{12 }*\frac{x }{ x^{-1/3} }*\frac{y^{-2} }{ y^{-5} }= \frac{1*4}{3*4}* x^{4/3}*y^{3}= \frac{1}{3} * x^{4/3}*y^{3}= \frac{x^{4/3}y^{3}}{3}
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3 years ago
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Step-by-step explanation:

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