This is my first time so don't get mad if i am wrong.
We know there are <u>2</u> quarters in the envelope and dimes, nickles, and pennies. and gives us an unknown number ?/? now we need to find those numbers. lets say d=dimes, n=nickles, and p=pennies. number example: d-1, n-3, p-2 next add these numbers which is 5+2=7.
Z / -4 < 2....multiply both sides by -4, cancelling out the -4 on the left. And dont forget to change the inequality sign because of multiplying by a negative.
z > 2 * -4
z > -8
Answer:
A. {y | -∞ < y < 4}
General Formulas and Concepts:
<u>Algebra I</u>
- Range is the set of y-values that are outputted by function f(x)<u>
</u>
Step-by-step explanation:
According to the graph, we can see that we have a horizontal asymptote at y = 4. Our y-values stretch from negative infinity to the horizontal asymptote.
∴ our answer would be A.
Answer: the probability of a student being overdrawn by more than $18.75 is 0.674
Step-by-step explanation:
Since the bank overdrafts of ASU student accounts are normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = bank overdraft of Asu students.
µ = mean
σ = standard deviation
From the information given,
µ = $21.22
σ = $5.49
We want to find the probability of a student being overdrawn by more than $18.75. It is expressed as
P(x > 18.75) = 1 - P(x ≤ 18.75)
For x = 18.75,
z = (18.75 - 21.22)/5.49 = - 0.45
Looking at the normal distribution table, the probability corresponding to the z score is 0.326
Therefore,
P(x > 18.75) = 1 - 0.326 = 0.674
Answer:
b.
Step-by-step explanation:
1. You have the following parent function given in the problem above:
f(x)=x³ (This is the simplest form. We need to translate it 3 units left and 2 units down)
2. If you take the parent function and make y=f(x+3), then you have:
(The function is shifted 3 units left on the x-axis).
3. Then you if you make y=f(x+3)-2, as following, you obtain:
(The function is shifted 2 units down on the y-axis).
4. Therefore, that is how you obtain the final function.
The answer is the graph shown in .b
