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3 years ago

Can someone do this?

Mathematics

1 answer:

malfutka [58]3 years ago

8 0

Answer:

Step-by-step explanation:

56+25%=70 (:

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Enter the exponents for the variables of the GCF of the following monomials.

miskamm [114]

The smallest exponents of the x and y term are 2. The Greatest Common Factor ( G C F ) for 9 x² y² and 5 x² y³ is: x² y².

8 0

3 years ago

Read 2 more answers

The distance from Kenya's house to her job is 18 miles. One morning she left her house at 7:15 a.m. She traveled at the rate of

Snezhnost [94]

20 minutes = 1/3 of an hour

1/3 = 0.333

1/3 x 45mph = 15, so she drove 15 miles at 45mph

18-15 = 3

3 miles/ 20 mph = 0.15 hours

0.333+0.15 = 0.483 hours total

0.483 x 60 = 28.98 so approximately 29 minutes total driving time

7:15 + 29 minutes is 7:44 am she arrived at work

8 0

3 years ago

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .

The number of fish tripled in the first year. This means that $P(1) = 3P(0) = 3(80) = 240$ .

Using the equation for P(1), that is, P(t) when $t = 1$ , we find the value of r.

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

$240 = \frac{2000*80e^{r}}{2000 + 80(e^{r} - 1)}$

$280*(2000 + 80(e^{r} - 1)) = 160000e^{r}$

$280*(2000 + 80e^{r} - 80) = 160000e^{r}$

$280*(1920 + 80e^{r}) = 160000e^{r}$

$537600 + 22400e^{r} = 160000e^{r}$

$137600e^{r} = 537600$

$e^{r} = \frac{537600}{137600}$

$e^{r} = 3.91$

Applying ln to both sides.

$\ln{e^{r}} = \ln{3.91}$

$r = 1.36$

This means that the expression for the size of the population after t years is:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

4 0

3 years ago

Please help me!!!!!<br>Appreciate it

fredd [130]

I'm working on something like this too.
You want to get the measure of y.

4x - 2y = 10
-4x -4x
------------------
-2y = 4x + 10
----- ---- ----
-2 -2 -2
y = -2/1x + -5
m = -2
b = -5
I think.....

3 0

4 years ago

What is 4(3.2d - 10) simplified

Levart [38]

Answer:

12.8d - 40

Step-by-step explanation:

Distributive property: Multiply the outside number with each of the numbers in the paranthesis.

FOLLOW - PEMDAS

Another way:

(4 • 3.2d) - (4 • 10)

(12.8d) - (40)

12.8d - 40

5 0

3 years ago