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Art [367]
2 years ago
10

Find the hypotenuse of an isosceles right triangle when the legs each measure 3\sqrt{x} 2inches.

Mathematics
1 answer:
Tresset [83]2 years ago
6 0

The hypotenuse of the right triangle measures 3 units.

<h3>How to find the hypotenuse?</h3>

Here we know that both legs measure:

L  =\frac{3}{\sqrt{2} }

If we use the Pythagorean theorem, we will see that the hypotenuse H can be written as:

H^2 = (\frac{3}{\sqrt{2} } )^2 +  (\frac{3}{\sqrt{2} } )^2 \\\\H^2 = \frac{9}{2} + \frac{9}{2} = \frac{18}{2} = 9\\\\H = \sqrt{9} = 3

Then we conclude that the hypotenuse of the right triangle measures 9 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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Triangle MNO is isosceles. Find the value of y and the measure of Angle O. Y=______
garri49 [273]

Answer:

y = -5

o = 35 degrees

Step-by-step explanation:

If you replace y with -5, the statement  7y = 4y - 15 is correct. You get -35 =  -35. Hope this helped!

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3 years ago
Pls help with both ............
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The time needed to complete a final examination in a particular college course is normallydistributed with a mean of 80 minutes
Artist 52 [7]

Answer:

a) 0.023

b) 0.286

c) 10 students will be unable to complete the exam inthe allotted time.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 80 minutes

Standard Deviation, σ = 10 minutes

We are given that the distribution of time to complete an exam is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(completing the exam in one hour or less)

P(x < 60)

P( x < 60) = P( z < \displaystyle\frac{60 - 80}{10}) = P(z < -2)

Calculation the value from standard normal z table, we have,  

P(x < 60) =0.023= 2.3\%

b) P(complete the exam in more than 60 minutes but less than 75 minutes)

P(60 \leq x \leq 75) = P(\displaystyle\frac{60 - 80}{10} \leq z \leq \displaystyle\frac{75-80}{10}) = P(-2 \leq z \leq -0.5)\\\\= P(z \leq -0.5) - P(z < -2)\\= 0.309- 0.023 = 0.286= 28.6\%

c) P(completing the exam in more than 90 minutes)

P(x > 90)

P( x > 90) = P( z > \displaystyle\frac{90 -80}{10}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 90) = 1 - 0.8413 = 0.1587 = 15.87\%

15.87% of children of class will require more than 90 minutes to complete the test.

Number of children =

\dfrac{15.87}{100}\times 60 = 9.52\approx 10

Approximately, 10 students of class will require more than 90 minutes to complete the test.

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4 years ago
Jake’s bank offers him an account with 3% interest, compoundedannually. How much interest would he earn from this account if hed
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I=P(1+R/100)^5
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Find the quotient of 3870 and 18
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The quotient is 215. 
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