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Art [367]
2 years ago
10

Find the hypotenuse of an isosceles right triangle when the legs each measure 3\sqrt{x} 2inches.

Mathematics
1 answer:
Tresset [83]2 years ago
6 0

The hypotenuse of the right triangle measures 3 units.

<h3>How to find the hypotenuse?</h3>

Here we know that both legs measure:

L  =\frac{3}{\sqrt{2} }

If we use the Pythagorean theorem, we will see that the hypotenuse H can be written as:

H^2 = (\frac{3}{\sqrt{2} } )^2 +  (\frac{3}{\sqrt{2} } )^2 \\\\H^2 = \frac{9}{2} + \frac{9}{2} = \frac{18}{2} = 9\\\\H = \sqrt{9} = 3

Then we conclude that the hypotenuse of the right triangle measures 9 units.

If you want to learn more about right triangles:

brainly.com/question/2217700

#SPJ1

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Determine the value of a + b in the system of equations below. <br><br> 5a + 4b = 22<br> 7a-b= 11
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Answer:

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Step-by-step explanation:

Here, we want go get the value of a and b

from the second equation, we can get an expression for b

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7a - b = 11

Thus,

b = 7a - 11

Now, from here, we can substitute the value of b into the first equation

We have this as;

5a + 4(7a - 11) = 22

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a = 66/33

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substituting the value of a from above;

b = 7(2) - 11

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