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Mashcka [7]
3 years ago
7

PLEASE HELP! ITS OVERDUE AND I CANT FIGURE IT OUT!!

Mathematics
1 answer:
earnstyle [38]3 years ago
3 0

Answer:

<u>Rectangle area is the product of its two adjacent sides:</u>

  • A = xy = 14

<u>Find each missing length</u>

  • xy = 14
  • y = 14 / x

1. x = 2 1/3 = 7/3

  • y = 14 ÷ 7/3 = 6

2. x = 4 1/5 = 9/5

  • y = 14 ÷ 9/5 = 70/9 = 7 7/9

3. x = 6/7

  • y = 14 ÷ 6/7 = 49/3 = 16 1/3

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An automobile engineer is redesigning a conical chamber that was originally specified to be 12 inches long with a circular base
kirill115 [55]

Answer:

the original volume is lesser than the new volume by 242.47 in³

Step-by-step explanation:

Volume of a cone is;

V = ⅓πr²h

Where;

r is radius

h is height

For the original chamber;

r = 5.7/2 = 2.85 inches

h = 12 inches

Volume of this original chamber is;

V_orig = ⅓ × π × 2.85² × 12

V_orig = 102.02 in³

In the new design, the chamber is scaled by a factor of 1.5.

Thus;

r_new = 2.85 × 1.5 = 4.275 inches

h_new = 12 × 1.5 = 18 inches

V_new = ⅓ × π × 4.275² × 18

V_new = 344.49 inch³

V_new - V_orig = 344.49 - 102.02 =

Thus, the original volume is lesser than the new volume by 242.47 in³

6 0
3 years ago
Y=-3x+2<br> y=4x-5<br> FInd the y slope. FInd the x slope.
mars1129 [50]

Both these expression are written in slope-intercept form. y = mx + b

m = slope

b = y-intercept

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y = 4x - 5 -> m = 4

Remember that m = slope

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5 0
3 years ago
A post is supported by two wires (one on each side going in oppositedirections) creating an angle of 80° between the wires. The
Vladimir [108]

Using the Sine rule,

\frac{\sin A}{A}=\frac{\sin B}{B}=\frac{\sin C}{C}\begin{gathered} \text{Let A = 14m,} \\ Substituting the variables into the formula,Where the length of the wires are, AP = xm and BP = ym[tex]\begin{gathered} \frac{\sin80^0}{14}=\frac{\sin40^0}{x} \\ \text{Crossmultiply,} \\ x\times\sin 80^0=14\times\sin 40^0 \\ Divide\text{ both sides by }\sin 80^0 \\ x=\frac{14\sin40^0}{\sin80^0} \\ x=9.14m \end{gathered}

Hence, the length of wire AP (x) is 9.14m.

For wire BP (y)m,

Sum of angles in a triangle is 180 degrees,

A^0+P^0+B^0=180^0\begin{gathered} \text{Where A}^0=\text{ unknown,} \\ P^0=80^0\text{ and,} \\ B^0=40^0 \\ A^0+80^0+40^0=180^0 \\ A^0+120^0=180^0 \\ A^0=180^0-120^0 \\ A^0=60^0 \end{gathered}

Using the side rule to find the length of wire BP,

\begin{gathered} \frac{\sin 60^0}{y}=\frac{\sin 80^0}{14} \\ \text{Crossmultiply,} \\ y\times\sin 80^0=14\times\sin 60^0 \\ \text{Didive both sides by }\sin 80^0 \\ y=\frac{14\times\sin 60^0}{\sin 80^0} \\ y=12.31m \end{gathered}

Hence, the length of wire BP (y) is 12.31m

Therefore, the length of the wires are (9.14m and 12.31m).

4 0
1 year ago
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