The formula for the lateral surface area of a cylinder is S=2πrhS=2πrh , where r is the radius of the bases and h is the height.
2 answers:
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Answer:
Step-by-step explanation:
Compare the ratios of the triangles like so:
Bigger to smaller
This statement is true. Both fractions simplified are equal to 1.5. Since they have the same ratios, they should be similar.
We know that
The Standard Form of a Quadratic Equation<span> looks like this
</span> ax²<span> + bx + c = 0
</span>
we have
<span>x -1 0 1 2 3
y -20 -6 2 4 0
for x=0 y=-6
then
</span> y=ax² + bx + c --------> -6=a*0² + b*0 + c ---------> c=-6
for y=0 x=3
then
y=ax² + bx + c-------> 0=a*3² + b*3 -6---------> 9a+3b=6----> equation 1
The Standard Form of a Quadratic Equation<span> looks like this
</span> ax²<span> + bx + c = 0
</span>
we have
<span>x -1 0 1 2 3
y -20 -6 2 4 0
for x=0 y=-6
then
</span> y=ax² + bx + c --------> -6=a*0² + b*0 + c ---------> c=-6
for y=0 x=3
then
y=ax² + bx + c-------> 0=a*3² + b*3 -6---------> 9a+3b=6----> equation 1
for x=2 y=4
then
y=ax² + bx + c-----> 4=a*2² + b*2 -6-----> 4=4a+2b-6-----> 4a+2b=10----> a=2.5-0.5b----> equation 2
I substitute 2 in 1
9*[2.5-0.5b]+3b=6------> 22.5-4.5b+3b=6------> 1.5b=16.5------> b=11
a=2.5-0.5*11------> a=2.5-5.5------> a=-3
The Standard Form of a Quadratic Equation is
ax² + bx + c = 0--------> -3x²+11x-6=0
the answer is
-3x²+11x-6=0
See the attached figure