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kondaur [170]
2 years ago
15

Rewrite the following expression without using absolute value. lz-6l-lz-5l if z<5

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
6 0

The expression without using absolute value is 2z - 11

<h3>Absolute value of a function</h3>

Given the expression with absolute value expressed as:

lz-6l-lz-5l

Since absolute function can both be negative or positive, hence;

lz-6l-lz-5l = z - 6 - -(z - 5)

lz-6l-lz-5l = z-6-(-z+5)

lz-6l-lz-5l = z - 6 + z - 5

lz-6l-lz-5l = 2z - 11

Hence the expression without using absolute value is 2z - 11

Learn more on absolute value here: brainly.com/question/729268

#SPJ1

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Answer:

a=\frac{2S -2v_ot-2s_o}{t^2}

Step-by-step explanation:

We have the equation of the position of the object

S = \frac{1}{2}at ^2 + v_ot+s_o

We need to solve the equation for the variable a

S = \frac{1}{2}at ^2 + v_ot+s_o

Subtract s_0 and v_0t on both sides of the equality

S -v_ot-s_o = \frac{1}{2}at ^2 + v_ot+s_o - v_ot- s_o

S -v_ot-s_o = \frac{1}{2}at ^2

multiply by 2 on both sides of equality

2S -2v_ot-2s_o = 2*\frac{1}{2}at ^2

2S -2v_ot-2s_o =at ^2

Divide between t ^ 2 on both sides of the equation

\frac{2S -2v_ot-2s_o}{t^2} =a\frac{t^2}{t^2}

Finally

a=\frac{2S -2v_ot-2s_o}{t^2}

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