Question

(2+1/2) (2^2-1+1/4) find the expression in the form of cubes and differences of two terms.​

Answer 1

Answer:

Consider the following identity:

• a³ - b³ = (a + b)(a² - ab + b²)

Let a = 2, b = 1/2

• (2 + 1/2)(2² - 2*1/2 + 1/2²) =
• 2³ - (1/2)³ =
• 8 - 1/8

Answer 2

Use the algebraic identity given below

$\boxed{\sf a^3-b^3=(a+b)(a^2-ab+b^2)}$

$\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-1+\dfrac{1}{4})$

$\\ \sf\longmapsto (2+\dfrac{1}{2})(2^2-2\times \dfrac{1}{2}+\dfrac{1}{2}^2)$

• Here a =2 and b=1/2

$\\ \sf\longmapsto 2^3-\dfrac{1}{2}^3$

$\\ \sf\longmapsto 8-\dfrac{1}{8}$