Answer:
So you would not be carried away by the tides
Step-by-step explanation:
hope this is what u want
Answer:
a) 
b) 
Step-by-step explanation:
By definition, we have that the change rate of salt in the tank is
, where
is the rate of salt entering and
is the rate of salt going outside.
Then we have,
, and

So we obtain.
, then
, and using the integrating factor
, therefore
, we get
, after integrating both sides
, therefore
, to find
we know that the tank initially contains a salt concentration of 10 g/L, that means the initial conditions
, so 

Finally we can write an expression for the amount of salt in the tank at any time t, it is 
b) The tank will overflow due Rin>Rout, at a rate of
, due we have 500 L to overflow
, so we can evualuate the expression of a)
, is the salt concentration when the tank overflows
Answer:
Option D. 1
Option E. 1/2
Step-by-step explanation:
we know that
Looking at the graph
The domain is the interval ----> [-1,1]

The domain is all real numbers greater than or equal to -1 and less than or equal to 1
The range is the interval ----> [0,1]

The range is all real numbers greater than or equal to 0 and less than or equal to 1
therefore
The values that are in the range are
1 and 1/2
Answer:
26/35
Step-by-step explanation:
Each fraction is increasing by 1/35. Therefore, 25/35 + 1/35 = 26/35.
Answer:
feet
Step-by-step explanation:
The depth of the fish to the surface of water at 1:00 pm = 2
feet
=
feet
The depth of the fish to its initial position at 4:00 pm = 3
feet
=
feet
The position of the fish with respect to the water's surface at 4:00 pm = the depth of the fish to the surface of water at 1:00 pm + the depth of the fish to its initial position at 4:00 pm
=
+ 
= 
= 
The position of the fish with respect to the water's surface at 4:00 pm is
feet.