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almond37 [142]
1 year ago
7

Please solve this exponential equation 3^2x-4(3^x+1)+27=0

Mathematics
1 answer:
Mumz [18]1 year ago
5 0

3²x-4(3²x+1)+27=0

9x-4(9x+1)+27=0

9x-4×9x-4×1+27=0

9x -36x -4 +27=0

9x-36x= 4-27

-27x= -23

x= -23/-27

x= 23/27

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