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2 years ago

What is the mean of 9, 25, and 53? 3 9 25 29

Mathematics

2 answers:

malfutka [58]2 years ago

4 0

Answer:

Step-by-step explanation:

9 + 25 + 53

87 ÷ 3

Artemon [7]2 years ago

4 0

Answer:

Step-by-step explanation:

add all the numbers up and divide by how many numbers there are.

You might be interested in

If the composition of two functions is:

NARA [144]

9514 1404 393

Answer:

x ≠ 3

Step-by-step explanation:

In any case, the domain is restricted to values of the variable for which the function is defined. The value 1/0 is not defined, so the variable cannot allow the denominator to be zero. The denominator x-3 will be zero for x=3, so that value of the variable cannot be in the domain.

The domain is all real numbers except x=3.

_____

Additional comments

It is useful to become familiar with the domains of different functions. As we saw above, the reciprocal of 0 is undefined. The square root of a negative number is undefined. The log of a non-positive number is undefined. Trig functions are defined everywhere, but their inverse functions are not. Polynomial functions are defined everywhere, but ratios of polynomials have the same restriction on denominators that we see above.

8 0

3 years ago

I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!

frutty [35]

Answer:

17) x=8

18) $x=\sqrt{189}$ or $x= 3\sqrt{21}$

Step-by-step explanation:

So the rule is $a^{2} +b^{2} =c^{2}$ , "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

$x^{2} +x^{2} =(8\sqrt{2}) ^{2}$

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

simplify (╥︣﹏╥)

$2x^2=8^2(\sqrt{2} )^{2}$

$2x^2=64(2)$

$2x^2=128$

$x^{2}= 128/2$

$x^{2} =64$

x=8

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

$c^{2} - b^{2} = a^{2}$

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

$15^{2} -6^{2} =x^{2}$

$225-36=x^{2}$

$x^{2} =189$

$x=\sqrt{189}=3\sqrt{21}$

The more you do these, the easier they'll get, so don't worry!

4 0

3 years ago

Suppose an=3an-1 -5an-2 -4an-3. and a4= -7, a5=-36, a6=-85 , find a1 , a2, a3

maria [59]

Answer:

$a_1=4\\\\a_2=0\\\\a_3=3$

Explanation:

The equation is:

$a_n=3a_{n-1}-5a_{n-2}-4a_{n-3}$

and

$a_4=-7, a_5=-36, a_6=-85$

1. Subsittute n = 6 into the equation:

$a_6=3a_{5}-5a_{4}-4a_{3}$

Now subsititute the known values:

$-85=3(-36)-5(-7)-4a_{3}$

You can solve for $a_3$

$-85=-108+35-4a_{3}\\\\4a_3=12\\\\a_3=12/4\\\\a_3=3$

2. Substitute n = 5 into the equation:

$a_5=3a_{4}-5a_{3}-4a_{2}$

Substitute the known values and solve for $a_2$

$-36=3(-7)-5(3)-4a_{2}\\\\4a_2=-21-15+36=0\\\\a_2=0$

3. Substitute n = 4 into the equation, subsitute the known values and solve for $a_1$

$a_4=3a_{3}-5a_{2}-4a_{1}$

$-7=3(3)-5(0)-4a_{1}\\\\4a_1=9+7=16\\\\a_1=4$

7 0

3 years ago

What is the factored form of x^2-x-2

tekilochka [14]

For this case we have:

By definition, the factorization is an algebraic expression that is used to find two or more factors, taking into account that the product of these factors must be equal to the given expression.

That is to say:

Given an expression of the form $x ^ 2 + (a + b) x + ab$