Answer:
The numerical limits for a B grade is between 81 and 89.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
B: Scores below the top 13% and above the bottom 56%
Below the top 13%:
Below the 100-13 = 87th percentile. So below the value of X when Z has a pvalue of 0.87. So below X when Z = 1.127. So
Above the bottom 56:
Above the 56th percentile, so above the value of X when Z has a pvalue of 0.56. So above X when Z = 0.15. So
The numerical limits for a B grade is between 81 and 89.
For this case we must find the quotient of the following expression:
We can rewrite the expression as:
(We take into account that
)
By definition of multiplication of powers of the same base, we place the same base and add the exponents:
By definition of division of powers of the same base, we place the same base and subtract the exponents:
Answer:
The angle between the vectors t and u is 45°. And the vector t and vector w are orthogonal to each other.
<h3>What is a vector?</h3>
The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
The vectors are given below.
t = −5i + 2j, u = −3i + 7j, and v = 8i + 20j
Part A: Then the angle between vectors t and u will be
Then we have
cos θ = [(−5i + 2j)(−3i + 7j)] / [√{(-5²) + 2²} + √{(-3)² + 7²}]
cos θ = 1 / √2
θ = 45°
Part B: c is a scalar
If 
, then 
Let c = 2, then we have
Part C: Use the dot product to determine if t and w are parallel or orthogonal.
More about the vector link is given below.
brainly.com/question/13188123
#SPJ1
There must be 23 students in Ms.Gardner's class because 23 - 30%=6.9 so 7
students are in her class are in the play because if you look at
Mr.Logan's class he has 23 students to and there are aslo 7 students in
his class are in the play so Mr. Logan's class is basically is holding
Ms.Gardner's place
oblique/slant asymptotes occur when the degree of the numerator is exactly 1 greater than that of the denominator
and the oblique asymptote occurs at the quotient of the rational expression, notice, since the denominator is just x - 3, doing a quick synthetic division will do to get the quotient.
