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Kisachek [45]
3 years ago
10

Three consecutive even integers have a sum of 48 . find the integers.

Mathematics
1 answer:
Mandarinka [93]3 years ago
4 0

<span>
</span>

<span>x+<span>(x+2)</span>+<span>(x+4)</span>=48</span>

3x+6=48

Minus 6 to both sides

<span>3x=42</span>

Divide 3 to both sides

<span>x=14</span>

Get the next two integers

<span>x,x+2,x+4 or 14,16,<span>18 = 48 is you Answer</span></span>

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dolphi86 [110]

Answer:

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Step-by-step explanation:

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Ok so first we find the equation that equals one variable.


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We solve for y.


2y = -x + 9

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Then we plug in this y value into the other equation to keep only one variable so we can solve for it.


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3(-x + 9/2) - 6y = -15

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Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.


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Your answer would be (-28/3, -3/18)


Hope this helps!

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