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2 years ago

Solve

Mathematics

1 answer:

viva [34]2 years ago

5 0

Answer:

cost was 252

Step-by-step explanation:

Show all work including equations

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a branch of mathematics that deals with the study of collecting, analyzing, interpreting, presenting, and organizing data in a p

saw5 [17]

Answer:

Statistics

Step-by-step explanation:

is the application of probability theory, a branch of mathematics, to statistics, as opposed to techniques for collecting statistical data.
the study and manipulation of data, including ways to gather, review, analyze, and draw conclusions from data.

7 0

2 years ago

Read 2 more answers

Solve the following system of equations graphically.

fiasKO [112]

Step-by-step explanation:

work is shown and pictured

8 0

3 years ago

Y-1.6+8.76 what is y

nikdorinn [45]

Answer:

there is no way of solving this because the expression does not equal anything.

Step-by-step explanation:

8 0

3 years ago

Samples of emissions from three suppliers are classified for conformance to air-quality specifications. The results from 100 sam

tigry1 [53]

Answer:

$P(A) = \frac{30}{100}$

$P(B) = \frac{77}{100}$

$P(A\ n\ B) = \frac{22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

Step-by-step explanation:

Given

See attachment for proper format of table

$n = 100$ --- Sample

A = Supplier 1

B = Conforms to specification

Solving (a): P(A)

Here, we only consider data in sample 1 row.

In this row:

$Yes = 22$ and $No = 8$

So, we have:

$n(A) = Yes + No$

$n(A) = 22 + 8$

$n(A) = 30$

P(A) is then calculated as:

$P(A) = \frac{n(A)}{Sample}$

$P(A) = \frac{30}{100}$

Solving (b): P(B)

Here, we only consider data in the Yes column.

In this column:

$(1) = 22$ $(2) = 25$ and $(3) = 30$

So, we have:

$n(B) = (1) + (2) + (3)$

$n(B) = 22 + 25 + 30$

$n(B) = 77$

P(B) is then calculated as:

$P(B) = \frac{n(B)}{Sample}$

$P(B) = \frac{77}{100}$

Solving (c): P(A n B)

Here, we only consider the similar cell in the yes column and sample 1 row.

This cell is: [Supplier 1][Yes]

And it is represented with; n(A n B)

So, we have:

$n(A\ n\ B) = 22$

The probability is then calculated as:

$P(A\ n\ B) = \frac{n(A\ n\ B)}{Sample}$

$P(A\ n\ B) = \frac{22}{100}$

Solving (d): P(A u B)

This is calculated as:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$

This gives:

$P(A\ u\ B) = \frac{30}{100} + \frac{77}{100} - \frac{22}{100}$

Take LCM

$P(A\ u\ B) = \frac{30+77-22}{100}$

$P(A\ u\ B) = \frac{85}{100}$

8 0

3 years ago

Rafael must choose a number between 67 and 113 that is a multiple of, 2,4, and 5 . Write all the numbers that he could choose.

skelet666 [1.2K]

First, find out what the greatest common factor is between 2, 4, and 5.

This is 20. So any number divisible by 20 is also divisible by 2, 4, and 5. 

Now we find the list of numbers that are multiples of 20 between 67 and 113. 

The solutions are: 

80 and 100.

5 0

3 years ago