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2 years ago

X+4

Mathematics

1 answer:

mr Goodwill [35]2 years ago

3 0

Answer:

Step-by-step explanation:

(x + 4)/(x+4)(x-3)

= 1/(x-3)

solution is option 4

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PLEASE SOMEONE HELP ME

posledela

My name is Sarai to, lol

6 0

3 years ago

Solve for A. BA + C = D 1)A = D-B-C 2)A = (D-C)/B 3)A = (C - D)B please hurry

enot [183]

I’m 95% sure the answer is 2

3 0

3 years ago

Challenge A gold mine has two elevators, one for equipment and another for the miners. The

OLEGan [10]

Step-by-step explanation:

The equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface

ii. The miners elevator is deeper than that of the equipment.

The speed of an object is the rate at which the object moves.

i.e speed = \frac{distance}{time}

time

distance

Thus,

Speed of the equipment elevator = 4 feet per second

Speed of the miners elevator = 15 feet per second.

Time of descent of the equipment elevator = 30 + 14

= 44 seconds

So that, the distance of the elevator at this time is;

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 4 x 44

= 176

distance = - 176 feet

The distance of the miners elevator after 14 seconds is:

speed = \frac{distance}{time}

time

distance

⇒ distance = speed x time

= 15 x 14

= 210

distance = - 210 feet

Thus after another 14 seconds, the equipment elevator is at a depth of 176 feet (-176 feet), while the miners elevator is at a depth of 210 feet (-210 feet) below the surface.

Therefore, the miners elevator is deeper than that of the equipment.

6 0

3 years ago

What's the solution to x^2-11x+19=-5 (this is a Quadratic Equation)

Maru [420]

Answer:

8 and 3

Step-by-step explanation:

We first want to add 5 to both sides, making the equation x^2 -11x +24=0, now, we want to use the quadratic formula, which is( -b + sqrt(b^2 -4ac)) /2a

for equations of the form ax^2 + bx +c, so in our case, a =1, b= -11, and c=24,

when you plug in the variables, you will get the answers! :)

4 0

3 years ago

Read 2 more answers

The function f(h)=m(1/2)^h gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life

goldfiish [28.3K]

Answer:

Third choice:

$f(x)=50(0.877)^{10};13.5mg$

Explanation:

1. Data:

Function:

$f(h)=m(1/2)^h$

Cobalt-60's half-life: 5.3 years

Initial mass of cobalt-60: 50 mg

2. Unknown:

equation for the mass of cobalt-60 remaining after 10 years = ?

mass remaining =?

3. Solution

Half-life is the time it takes a sample to decay to half of its initial amount. It is considered constant. Hence, when one half-life passes, the sample has decayed to 50% of the original amount; when two half-lives pass, the sample has decayed to (1/2)×(1/2) = 1/4 = 25%; when three half-lives have elapsed, the sample has decayed to (1/2)³ = 1/8 = 12.5% of its original amount, and so on.

Then, the amound of a sample remaining is calculated as the original amount times (1/2) raised to the number of half-lives elapsed, which is what the given function, $f(h)=m(1/2)^h$ models.

You just must substitute the data into the function to get the answer to the question:

$f(x)=50(0.5)^{(10/5.3)}$

Where, 50 is the original mass of 50g, 0.5 is equal to 1/2, and 10/5.3 gives the number of half-lives (the number of times that 5.3 years is contained in 10 years).

Simplifying:

$f(x)=50(0.5)^{(10/5.3)}=50((0.5)^{(1/5.3})^{10}\approx50(0.877)^{10}$

Which corresponds to the third choice of the list.

Computing:

$f(x)\approx50(0.877)^{10}=13.5$

Which also corresponds to the third choice.

4 0

3 years ago

Read 2 more answers