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beks73 [17]
2 years ago
12

Which equation represents a line that passes through (4, left-parenthesis 4, StartFraction one-third EndFractin right-parenthesi

s.) and has a slope of StartFraction 3 Over 4 EndFraction.?
y – y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis. = y minus StartFraction 3 Over 4 EndFraction equals StartFraction one-third EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)
y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)
y – y minus StartFraction one-third EndFraction equals 4 left-parenthesis x minus StartFraction 3 Over 4 EndFraction right-parenthesis. = 4(x – )
y – 4 = y minus 4 equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus StartFraction one-third EndFraction right-parenthesis.(x – )
Mathematics
1 answer:
sladkih [1.3K]2 years ago
4 0

The equation represents a line that passes through(4, 1/3) and has a slope of 3/4 option A; y - 1/3 = 3/4 ( x - 4).

<h3>What is the Point-slope form?</h3>

The equation of the straight line has its slope and given point.

If we have a non-vertical line that passes through any point(x1, y1) has gradient m. then general point (x, y) must satisfy the equation

y-y₁ = m(x-x₁)

Which is the required equation of a line in a point-slope form.

we know that            

The equation of the line into point-slope form is equal to                        

y-y₁ = m(x-x₁)

             

we have          

(x₁, y₁) = (4, 1/3)

m = 3/4

 

substitute the given values                

y-y₁ = m(x-x₁)

y - 1/3 = 3/4 ( x - 4)

therefore,

y minus StartFraction one-third EndFraction equals StartFraction 3 Over 4 EndFraction left-parenthesis x minus 4 right-parenthesis.(x – 4)

Thus, option A is correct.

Learn more about slope;

brainly.com/question/13458632

#SPJ1

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0.0903

Step-by-step explanation:

Given that :

The mean = 1450

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sample mean = 1560

P(X > 1560) = P( Z > \dfrac{x - \mu}{\sigma})

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Let consider the given number of weeks = 52

Mean \mu_x = np = 52 × 0.3085 = 16.042

The standard deviation =  \sqrt {n \time p (1-p)}

The standard deviation = \sqrt {52 \times 0.3085 (1-0.3085)}

The standard deviation = 3.3306

Let Y be a random variable that proceeds in a binomial distribution, which denotes the number of weeks in a year that exceeds $1560.

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P(Y > 20) \simeq 0.0903

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3 years ago
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