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Effectus [21]
2 years ago
12

In which table does yvary directly with x?

Mathematics
1 answer:
anzhelika [568]2 years ago
4 0

The table in which y varies directly with x is table C.

<h3>What is direct variation?</h3>

When a variable varies directly with another variable, it means that as one variable increases, the other variable also increases.

The equation that is used to represent direct variation is:

y = kx

Where y is the constant of proportionality

In table c, k is equal to 26

  • 26 x 2 = 54
  • 26 x 3 = 78

To learn more about direct variation, please check: brainly.com/question/27573249

#SPJ1

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In p.
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The circumference by definition is given by:
 C = 2 * pi * r
 Where,
 r: radius of the circle.
 Substituting values we have:
 C = 2 * 3.14 * 16
 C = 100.48 feet
 Answer:
 
A measurement that is closest to the circumference of the parachute in feet is:
 
C = 100.48 feet
6 0
3 years ago
The picture below shows Annie and her younger brother Tommy’s money. They want to combine their money to buy something together.
Inga [223]

Answer:

$5.47

Step-by-step explanation:

Given data:

Annie has 4 dollar , 11 dimes, 4 pennies.

Tommy has 3 dimes, 3 pennies.

To add the money, let us first convert dime and penny into dollar.

1 dollar = $1

11 dime = $1.1

4 penny = $0.04

3 dime = $0.3

3 penny = $ 0.03

Total money = Annie’s money + Tommy’s money

                     = $4 + $1.1 + $ 0.04 + $0.3 + $0.03

                     = $5.47

So, they have $5.47 in all.

5 0
4 years ago
Read 2 more answers
The area of a circle with radius r is given by A = π r2. Find the area of a circle with radius 7 centimeters. Use 3.14 for π..
scZoUnD [109]

Step-by-step explanation:

Hey there!

Given;

Radius of a circle (r) = 7cm

Now;

We know that;

Area of circle (a) = π*(r^2)

= 3.14*(7^2)

= 3.14*49

= 153.86 cm^2

Therefore, the area of a circle is 153.86 cm^2.

<em><u>Hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

4 0
3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

4 0
4 years ago
Hardest question in world
Morgarella [4.7K]

Answer:

every answer is correct

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
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