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vova2212 [387]
3 years ago
10

Jeremy opens a chocolate shop in the city. He pays $1,500 a month for rent and maintenance of the shop. The price of raw materia

ls and manufacturing the chocolates is $6,000 a month. He sells the chocolates individually and in boxes of a dozen.
Jeremy understands that his business needs a little time to become a success and decides that he wants to build a customer base initially. He is happy to break even for the first year.

After a year, Jeremy prices his chocolates at $3 apiece. He offers a discount of 10% on boxes of chocolate to promote the sale of boxes. How many boxes of chocolate would he have to sell to recover the cost of running the business this year per month? (Assume that he sells no individual chocolates.)


A.188 boxes



B.208 boxes



C.226 boxes



D.232 boxes
Mathematics
2 answers:
kirza4 [7]3 years ago
8 0
Hey friend!


232 is the answer!
adoni [48]3 years ago
4 0
1500 + 6000 = 0.9(3 * 12)x
7500 = 32.4x
7500/32.4 = x
231.48 = x......hmmm...not quite...I would go with 232


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Use complete sentences to describe why √-1 ≠ -√1
tekilochka [14]

Well let's say that to compare these two numbers, we have to start with the definition first.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u>

\displaystyle \large{ {y}^{2}  = x} \\  \displaystyle \large{ y =  \pm  \sqrt{x} }

Looks like we can use any x-values right? Nope.

The value of x only applies to any positive real numbers for one reason.

As we know, any numbers time itself will result in positive. No matter the negative or positive.

<u>D</u><u>e</u><u>f</u><u>i</u><u>n</u><u>i</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>I</u><u>I</u>

\displaystyle \large{  {a}^{2}  = a \times a =  |b| }

Where b is the result from a×a. Let's see an example.

<u>E</u><u>x</u><u>a</u><u>m</u><u>p</u><u>l</u><u>e</u><u>s</u>

\displaystyle \large{  {2}^{2}  = 2 \times 2 = 4} \\  \displaystyle \large{  {( - 2)}^{2}  = ( - 2) \times ( - 2) =  | - 4|  = 4}

So basically, their counterpart or opposite still gives same value.

Then you may have a question, where does √-1 come from?

It comes from this equation:

\displaystyle \large{   {y}^{2}  =  - 1}

When we solve the quadratic equation in this like form, we square both sides to get rid of the square.

\displaystyle \large{   \sqrt{ {y}^{2} } =   \sqrt{ - 1}  }

Then where does plus-minus come from? It comes from one of Absolute Value propety.

<u>A</u><u>b</u><u>s</u><u>o</u><u>l</u><u>u</u><u>t</u><u>e</u><u> </u><u>V</u><u>a</u><u>l</u><u>u</u><u>e</u><u> </u><u>P</u><u>r</u><u>o</u><u>p</u><u>e</u><u>r</u><u>t</u><u>y</u><u> </u><u>I</u>

\displaystyle \large{  \sqrt{ {x}^{2}  } =  |x|  }

Solving absolute value always gives the plus-minus. Therefore...

\displaystyle \large{  y =   \pm \sqrt{ - 1}  }

Then we have the square root of -1 in negative and positive. But something is not right.

As I said, any numbers time itself of numbers squared will only result in positive. So how does the equation of y^2 = -1 make sense? Simple, it doesn't.

Because why would any numbers squared result in negative? Therefore, √-1 does not exist in a real number system.

Then we have another number which is -√1. This one is simple.

It is one of the solution from the equation y^2 = 1.

\displaystyle \large{   {y}^{2}  = 1} \\  \displaystyle \large{    \sqrt{ {y}^{2} }  =  \sqrt{1} } \\  \displaystyle \large{  y  =  \pm  \sqrt{1} }

We ignore the +√1 but focus on -√1 instead. Of course, we know that numbers squared itself will result in positive. Since 1 is positive then we can say that these solutions exist in real number.

<u>C</u><u>o</u><u>n</u><u>c</u><u>l</u><u>u</u><u>s</u><u>i</u><u>o</u><u>n</u>

So what is the different? The different between two numbers is that √-1 does not exist in a real number system since any squared numbers only result in positive while -√1 is one of the solution from y^2 = 1 and exists in a real number system.

5 0
3 years ago
Read 2 more answers
Harry buys a TV priced at £1200 plus 20% VAT.
RoseWind [281]

Answer:

£ 114

Step-by-step explanation:

From the question given above, the following data were obtained:

Price of TV = £ 1200

VAT = 20%

Amount paid = £ 300

Amount paid monthly =.?

Next, we shall determine the VAT. This can be obtained as follow:

VAT = 20% of price of TV

VAT = 20/100 × 1200

VAT = £ 240

Next, we shall determine the total cost of the TV. This can be obtained as follow:

Price of TV = £ 1200

VAT = £ 240

Total cost of TV =?

Total cost = Price + VAT

Total cost = 1200 + 240

Total cost = £ 1440

Next, we shall determine the balance amount he needs to pay. This can be obtained as follow:

Total cost = £ 1440

Amount paid = £ 300

Balance amount =?

Balance = Total cost – Amount paid

Balance = 1440 – 300

Balance = £ 1140

Finally, we shall determine the amount Harry will pay month.

Balance Amount = £ 1140

Number of months = 10

Amount paid monthly =.?

Amount paid monthly = Balance / number of month

Amount paid monthly = 1140 / 10

Amount paid monthly = £ 114

Therefore, Harry will pay £ 114 monthly.

4 0
3 years ago
A book store offers a sale on a new book. The sale is "buy two of the books and get the third book free." Tommy pays $26 for thr
Molodets [167]

Answer:

Salvo en cada library 4.33

3 0
3 years ago
More help is appreciated:))
Lera25 [3.4K]

Step-by-step explanation:

You need to translate all the points to the right 3 and up 6

Therefore, you are going to use this formula:

(x,y) ⇾ (x + 3, y + 6)

This is the same format as the previous problem, if you have noticed.

Using this, plug in each coordinate, starting with  P (5, -1)

(5, -1) ⇾ ( 5 + 3, -1 + 6)

(5, -1) ⇾ ( 8, 5 )

P^{1} = (8, 5)

Now point Q, (0, 8)

(0, 8) ⇾ (0 + 3, 8 + 6)

(0, 8) ⇾ ( 3, 14 )

Q^{1} = (3, 14)

And last but not least, the point R, (7, 5)

(7, 5) ⇾ (7 + 3, 5 + 6)

(7, 5) ⇾ ( 10, 11 )

R^{1} = (10, 11)

Therefore, P^{1} = (8, 5), Q^{1} = (3, 14), R^{1} = (10, 11) is your answer. This is the 4th option or D.

Hope this for you to understand this a bit more! =D

6 0
3 years ago
For the given line segment, write the equation of the perpendicular bisector.
Jlenok [28]

Answer:

D) y = -4/5x – 47/10

Step-by-step explanation:

Step 1. Find the <em>midpoint of the segmen</em>t.

The two end points are (-6, -4) and (-2, 1).

The midpoint is at the average of the coordinates.

(xₚ, yₚ) = ((x₁ + x₂)/2, (y₁ + y₂)/2)

(xₚ, yₚ) = ((-6 - 2)/2, (-4 + 1)/2)

(xₚ, yₚ) = (-8/2, -3/2)

(xₚ, yₚ) = (-4, -3/2)

===============

Step 2. Find the <em>slope (m₁) of the segment</em>

m₁ = (y₂ - y₁)/(x₂ - x₁)

m₁ = (1 - (-4))/(-2 - (-6))

m₁ = (1 + 4)/(-2 + 6)

m₁ = 5/4

===============

Step 3. Find the <em>slope (m₂) of the perpendicular bisector </em>

m₂ = -1/m₁

m₂ = -4/5

====================

Step 4. Find the <em>intercept of the perpendicular bisector</em>

y = mx + b

y = -(4/5)x + b

The line passes through (-4, -3/2).

-3/2 = -(4/5)(-4) + b

-3/2 = 16/5 + b      Multiply each side by 10

 -15 = 32 + 10 b    Subtract 32 from each side

 -47 = 10b             Divide each side by 10

    b = -47/10

===============

Step 5. Write the <em>equation for the perpendicular bisector</em>

y = -4/5x – 47/10

The graph shows the midpoint of your segment at (-4, -3/2) and the perpendicular bisector passing through the midpoint and (0, -47/10).

4 0
4 years ago
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