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vova2212 [387]
3 years ago
10

Jeremy opens a chocolate shop in the city. He pays $1,500 a month for rent and maintenance of the shop. The price of raw materia

ls and manufacturing the chocolates is $6,000 a month. He sells the chocolates individually and in boxes of a dozen.
Jeremy understands that his business needs a little time to become a success and decides that he wants to build a customer base initially. He is happy to break even for the first year.

After a year, Jeremy prices his chocolates at $3 apiece. He offers a discount of 10% on boxes of chocolate to promote the sale of boxes. How many boxes of chocolate would he have to sell to recover the cost of running the business this year per month? (Assume that he sells no individual chocolates.)


A.188 boxes



B.208 boxes



C.226 boxes



D.232 boxes
Mathematics
2 answers:
kirza4 [7]3 years ago
8 0
Hey friend!


232 is the answer!
adoni [48]3 years ago
4 0
1500 + 6000 = 0.9(3 * 12)x
7500 = 32.4x
7500/32.4 = x
231.48 = x......hmmm...not quite...I would go with 232


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Damm [24]

Answer:

17

Step-by-step explanation:

4 × 3² = 36

2 × 7 = 14

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3 ± 14 = 17

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3 years ago
Do students tend to improve their SAT mathematics (SAT-M) score the second time they take the test? A random sample of four stud
emmainna [20.7K]

Answer:

b

Step-by-step explanation:

We will conduct a hypothesis test for dependent samples since the same subjects were retested.  

We first need to find the difference in scores

Student 1:  450 - 440 = 10

Student 2:  520 - 600 = -80

Student 3:  720 - 720 = 0

Student 4:  600 - 630 = -30

Now find the mean of the differences: d =  (10 - 80 + 0 - 30)/4 = -100/4 = -25

Now find the standard deviation, which is the square root of the variance:

[(10 - (-25))² + (-80 - (-25))² + (0 - (-25))² + (-30 - (-25))²]/(4*3) =

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Find the test statistic:  t = (d - µ)/(s/√n)

t = (-25 - 0)/(20.2073/√4) = -2.474

For a critical region of this two tailed test, for a 90% significance level, we get a t-value of:  t < -2.353 or t > 2.353, since our test statistic is in this region, b is a valid answer

For a critical region of this two tailed test, for a 99% significance level, we get a t-value of:  t < -5.841 or t > 5.841, since our test statistic isn't in this region, c is not a valid answer

8 0
3 years ago
I NEED YOUR HELP PLEASE GRADES ARE DUE TODAY AND I DONT KNOW HOW TO DO THIS.​
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Answer:

#1 c. -1

#2 b. 1 is less than or equal to x which is less than or equal to three

#3 a. 37.5 is less than or equal to y which is less than or equal to 87.5

#4 b. 3

#5 b. (2, 3, 4, 5, 6)

#6 d. (45, 55, 65, 75, 85)

Step-by-step explanation:

Domain is the x value and y is the range. For #1 the answer is c because you can't go golfing for -1 hours. For #2, the answer is b because they are all the acceptable values for the domain which is represented by x and x is the time spent at the golfing bay. The answer would not be c because you could go to the bay for 2.75 hours it doesn't have to be just 1, 2, 3.  For #3 the concept is similar because the range aka total cost can be all the values in between 37.5 and 87.5. For #4  a reasonable domain value which is number of people is 3 because you can't have 2.5 people and you can't have -4 people and thus all of the above isn't possible leaving three. #5 is b because you can only have those set numbers to represent people. If you chose a that would mean you could have 1.5 people which isn't possible thus only numbers 2, 3, 4, 5, and 6 are possible. For #6 The answer is d because when you plug in numbers 2, 3, 4, 5, 6 into the x value one at a time and solve the equation, those numbers equal t. Just use your basic knowledge to figure these out there isn't much math you just have to know that domain means x and range means y. y is 9/10 always by itself on one side of the equal sign. When in doubt think, can I have a half a person. Think of the real world and apply to math. Goof luck on future problems!

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Answer:

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Step-by-step explanation:

\int\limits^1_1 x^3 \, dx  -  \int\limits^1_1 {x} \, dx

Limits should be -1 to 1, its the integral of x^3 from -1 to 1 minus the integral of x from -1 to 1.

0-0 = 0

8 0
3 years ago
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