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vova2212 [387]
3 years ago
10

Jeremy opens a chocolate shop in the city. He pays $1,500 a month for rent and maintenance of the shop. The price of raw materia

ls and manufacturing the chocolates is $6,000 a month. He sells the chocolates individually and in boxes of a dozen.
Jeremy understands that his business needs a little time to become a success and decides that he wants to build a customer base initially. He is happy to break even for the first year.

After a year, Jeremy prices his chocolates at $3 apiece. He offers a discount of 10% on boxes of chocolate to promote the sale of boxes. How many boxes of chocolate would he have to sell to recover the cost of running the business this year per month? (Assume that he sells no individual chocolates.)


A.188 boxes



B.208 boxes



C.226 boxes



D.232 boxes
Mathematics
2 answers:
kirza4 [7]3 years ago
8 0
Hey friend!


232 is the answer!
adoni [48]3 years ago
4 0
1500 + 6000 = 0.9(3 * 12)x
7500 = 32.4x
7500/32.4 = x
231.48 = x......hmmm...not quite...I would go with 232


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Let x represent lower level tickets that cost $77

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Using the elimination method, multiply the second equation by -77:

77x + 99y = 247,071

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--> y = 2,078

Now plug "y" into either equation and solve for "x". I chose the Tickets equation. x + y = 2615 → x = 2615 - y → x = 2615 - 2078 → x = 537

Answer: lower level = 537 tickets, upper level = 2078 tickets.


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3 years ago
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Answer:

1 in 15 chance

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What is 5/7 equivalent to
Lina20 [59]
If you're looking for the decimal it is

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Using the distributive property is done by multiplying the factor (outside the parentheses) to each term within it. In this case, 8(3 + 4), we multiply the 8 by 3, and then add it to the product of 8 x 4:
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