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ella [17]
3 years ago
5

(URGENT!!!! WILL MAKE BRAINLIEST) Write a quadratic equation with -4 and 3/2 as its roots. Write the equation in the form ax² +

bx + c = 0, where a, b, and c are integers. SHOW YOUR WORK!
Mathematics
1 answer:
LekaFEV [45]3 years ago
5 0

Answer:

2X^2+5/2X-3/2=0

Step-by-step explanation:

To identify the equation use the following method

(X-a)(X-b)=0

Put values

a=-4

b=3/2

(X+4)(X-3/2)=0

X^2+4X-3/2X-3/2=0

X^2+(8X-3X)/2-3/2=0

X^2+5/2X-3/2=0

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F(13)=45,000(0.9)^13
Nadusha1986 [10]

Answer:

About 879.877

Step-by-step explanation:

To find f,

f(13) = 45,000(0.9)^13

13f = 45,000(0.25418658283)

13f = 11438.3962274

f = 879.877

Please tell me I did this the right way, Thanks!

3 0
3 years ago
Which integer CANNOT be a solution to the inequality 6x − 4 ≤ 7x − 3 ?
mezya [45]

Answer:

0

Step-by-step explanation:

4 0
3 years ago
there are 200 end of the year school dance tickets students who have perfect attendance are able to presage them in advance if 1
Umnica [9.8K]

200 - 18 = 182
182 is the answers
3 0
3 years ago
12/15,3/4,3/12 as a decimal/ how to get the answer
Darya [45]
Your answer is C I’m sure about that!
6 0
4 years ago
A positive integer is twice another.the sum of the reciprocal of the two positive integer is 3/14. Find the integers
icang [17]

Answer:

\huge\boxed{14\ \text{and}\ 7}

Step-by-step explanation:

n,\ m-\text{positive integer}\\\\n=2m-\text{a positive integer is twice another}\\\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}-\text{the sum of the reciprocal of the two positive integer is }\ \dfrac{3}{14}\\\\\text{We have the system of equations:}\\\\\left\{\begin{array}{ccc}n=2m&(1)\\\dfrac{1}{n}+\dfrac{1}{m}=\dfrac{3}{14}&(2)\end{array}\right

\text{Substitute (1) to (2):}\\\\\dfrac{1}{2m}+\dfrac{1}{m}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{1\cdot2}{m\cdot2}=\dfrac{3}{14}\\\\\dfrac{1}{2m}+\dfrac{2}{2m}=\dfrac{3}{14}\\\\\dfrac{1+2}{2m}=\dfrac{3}{14}\\\\\dfrac{3}{2m}=\dfrac{3}{14}\Rightarrow2m=14\qquad\text{divide both sides by 2}\\\\\dfrac{2m}{2}=\dfrac{14}{2}\\\\\boxed{m=7}

\text{Substitute it to (1):}\\\\n=2\cdot7\\\\\boxed{n=14}

8 0
3 years ago
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