Answer:
2X^2+5/2X-3/2=0
Step-by-step explanation:
To identify the equation use the following method
(X-a)(X-b)=0
Put values
a=-4
b=3/2
(X+4)(X-3/2)=0
X^2+4X-3/2X-3/2=0
X^2+(8X-3X)/2-3/2=0
X^2+5/2X-3/2=0
Let number if boys be x
ATQ
I think it is a maximum value.
a
y=(-x^2)+12x-20
=(-(3)^2)+12(3)-20
=(-9)+36-20
=16-9=7
y=7
I hope it helped you