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2 years ago

How many solutions exist for the given equation? 12x 1 = 3(4x 1) – 2

Mathematics

1 answer:

Helen [10]2 years ago

5 0

The equation has infinite many solutions

<h3>How to determine the number of solutions?</h3>

The equation is given as:

12x + 1 = 3(4x + 1) - 2

Open the brackets

12x + 1 = 12x + 3 - 2

Evaluate the like terms

12x + 1 = 12x + 1

Both sides of the equation are the same

This means that the equation has infinite many solutions

Read more about equation solutions at:

brainly.com/question/13729904

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Find the value of annuity if the periodic deposit is $1500 at 8% compounded semiannually for 22 years

Jet001 [13]

Answer:

The value of annuity is $P_v = \$ 32058$

Step-by-step explanation:

From the question we are told that

The periodic payment is $P = \$ 1500$

The interest rate is $r = 8\% = 0.08$

Frequency at which it occurs in a year is n = 2 (semi-annually )

The number of years is $t = 22 \ years$

The value of the annuity is mathematically represented as

$P_v = P * [1 - (1 + \frac{r}{n} )^{-t * n} ] * [\frac{(1 + \frac{r}{n} )}{ \frac{r}{n} } ]$ (reference EDUCBA website)

substituting values

$P_v = 1500 * [1 - (1 + \frac{0.08}{2} )^{-22 * 2} ] * [\frac{(1 + \frac{0.08}{2} )}{ \frac{0.08}{2} } ]$

$P_v = 1500 * [1 - (1.04 )^{-44} ] * [\frac{(1.04 )}{0.04} ]$

$P_v = 1500 * [1 - 0.178 ] * [\frac{(1.04 )}{0.04} ]$

$P_v = \$ 32058$

8 0

3 years ago

Write the inequality. John spent less than $28 on a magazine and six

sergij07 [2.7K]

28lt5+6z hope this helps

4 0

3 years ago

Find an equation of the plane that is parallel to the line of intersection of the planes ( x + 3y + z = 3 ) ( 3x - y - z = 0 ) a

NeTakaya

Answer:

Wow I got the first step

are you looking for the

intersection of the line perpendicular

to plane 1 thorough the origin and plane 2

for the first part???

7 0

3 years ago

HELP!! pie/3 is the reference angle for:

LuckyWell [14K]

Answer:

A, C and D.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Verify the identity. cotangent of x divided by quantity one plus cosecant of x equals quantity cosecant of x minus one divided b

Elenna [48]

Answer:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Step-by-step explanation:

We want to verify the identity:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

Let us take the LHS and simplify to get the LHS.

Express everything in terms of the cosine and sine function.

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{1+\frac{1}{\sin x} }$

Collect LCM

$\frac{\cot x}{1+\csc x}=\frac{\frac{\cos x}{\sin x} }{\frac{\sin x+1}{\sin x} }$

We simplify the RHS to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x}{\sin x+1}$

We rationalize to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{(\sin x+1)*(\sin x-1)}$

We expand to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{\sin^2 x-1}$

Factor negative one in the denominator:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-(1-\sin^2 x)}$

Apply the Pythagoras Property to get:

$\frac{\cot x}{1+\csc x}=\frac{\cos x(\sin x-1)}{-\cos^2 x}$

Simplify to get:

$\frac{\cot x}{1+\csc x}=\frac{-(\sin x-1)}{\cos x}$

$\frac{\cot x}{1+\csc x}=\frac{1-\sin x}{\cos x}$

Divide both the numerator and denominator by sin x

$\frac{\cot x}{1+\csc x}=\frac{\frac{1}{\sin x}-\frac{\sin x}{\sin x}}{\frac{\cos x}{\sin x}}$

This finally gives:

$\frac{\cot x}{1+\csc x}=\frac{\csc x-1}{\cot x}$

8 0

3 years ago