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irga5000 [103]
3 years ago
9

Through which two points could a line of rotation be placed so that the base of the resulting cylinder will have a radius of 5 c

m?
D and E


B and D


C and F


G and H
Mathematics
2 answers:
vagabundo [1.1K]3 years ago
4 0

Answer:

G and H

Step-by-step explanation:

just took the test in edg.

bija089 [108]3 years ago
3 0

Answer:

Its D :)

Step-by-step explanation:

You might be interested in
<img src="https://tex.z-dn.net/?f=0.2%2810-5c%29%20%3D%205c%20-%2016" id="TexFormula1" title="0.2(10-5c) = 5c - 16" alt="0.2(10-
san4es73 [151]

We are given,

\longrightarrow 0.2(10 - 5c) = 5c - 16

Solving the parenthesis

{ \longrightarrow 0.2 \times 10 - 0.2 \times 5c = 5c - 16 }

{ \longrightarrow 2 - 1c = 5c - 16 }

{ \longrightarrow 2  + 16 = 5c + 1c }

{ \longrightarrow  18  = 6c }

Dividing both sides by 6

{ \longrightarrow  3 = c }

Hence c = 3.

8 0
3 years ago
Estimate the square root of 150 to the nearest tenth.
muminat

the answer is 12.2 for 150 rounded to nearest tenth

5 0
3 years ago
Read 2 more answers
Luke and isabella make scale drawings.The scale from isabella's drawing is 6 m to 3 cm. The height of the fountain in isabella's
den301095 [7]

Answer:

The answer is "2.5 \ cm"

Step-by-step explanation:

While Luke is 5m to 2cm in size, it implies that every 2cm to Luke's drawing is 5m in real life. That real pond width must therefore be 5 m, given the fountain's width is 2 cm. As shown in the illustration, the step size for IsabelLa from the illustration to real life is \frac{6}{3} =2, which makes it simple to multiply any measure in the cm of her illustration by 2 to accomplish the exact size in m. So, in another direction around, they just have to divide the value by 2, instead of the divide from reality for drawing. So if the actual worth is 5m, it ought to be \frac{5}{2} = 2.5 \ cm in its width.

7 0
2 years ago
How does the graph y=3^x compare to the graph y=3^-x
LUCKY_DIMON [66]

Answer:

Y = 3x^x is a graph that has exponential growth while y = 3^-x has exponential decay.

Y = 3x^x (-∞, 0) and (∞, ∞).

Y = 3x^-x (-∞, ∞) and (∞, 0).

Step-by-step explanation:

The infinity symbols were being used to represent the x and y values of each graph. I will call y = 3^x "graph 1" and y = 3^-x "graph 2".

When graph 1 had positive ∞ for its x value, its y value was reaching towards positive ∞. When its x was reaching for negative ∞, its y was going for 0.

For graph 2, however, when its x was reaching for positive ∞, its x was reaching for 0. When its x was reaching for negative ∞, its y was going for positive ∞.

Here's an image of the graphs:

5 0
3 years ago
For which interval does this quadratic inequality hold true?
adoni [48]

Answer:

D

Step-by-step explanation:

x²-4x-12≤0

x²-6x+2x-12≤0

x(x-6)+2(x-6)≤0

(x-6)(x+2)≤0

x=6,-2

∴ value of x lies between -2 & 6

3 0
1 year ago
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